What is the general solution for sin(A)=-1/2 ?

The general solution for sin(A)=-1/2 is A=(7pi)/6+2pin,A=(11pi)/6+2pin

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sin(A)=-1/2

sin (A) = - \frac{1}{2}

A = \frac{7 π}{6} + 2 πn, A = \frac{11 π}{6} + 2 πn

Degrees

A = 21 0^{\circ} + 36 0^{\circ} n, A = 33 0^{\circ} + 36 0^{\circ} n

Solution steps

sin (A) = - \frac{1}{2}

General solutions for

sin (A) = - \frac{1}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

A = \frac{7 π}{6} + 2 πn, A = \frac{11 π}{6} + 2 πn

A = \frac{7 π}{6} + 2 πn, A = \frac{11 π}{6} + 2 πn

6 tan (x) + 1 = 4 tan (x) + 3

cos (x) = \frac{- 5}{5}

cos (A) = \frac{4 ^{2} + ( 5.1 ) ^{2} - 3 ^{2}}{2 - 4 \cdot 5.1}

cos (a) = \frac{5}{4}

1 - 2 sin^{2} (x) = \frac{1}{2}

What is the general solution for sin(A)=-1/2 ?
The general solution for sin(A)=-1/2 is A=(7pi)/6+2pin,A=(11pi)/6+2pin