What is the general solution for sin(t)= 1/2 ,0<= t< pi/2 ?

The general solution for sin(t)= 1/2 ,0<= t< pi/2 is t= pi/6

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sin(t)= 1/2 ,0<= t< pi/2

sin (t) = \frac{1}{2}, 0 \leq t < \frac{π}{2}

t = \frac{π}{6}

Degrees

t = 3 0^{\circ}

Solution steps

sin (t) = \frac{1}{2}, 0 \leq t < \frac{π}{2}

General solutions for

sin (t) = \frac{1}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

t = \frac{π}{6} + 2 πn, t = \frac{5 π}{6} + 2 πn

t = \frac{π}{6} + 2 πn, t = \frac{5 π}{6} + 2 πn

Solutions for the range

0 \leq t < \frac{π}{2}

t = \frac{π}{6}

tan (θ) = 1.4

sin (θ) = - 0.8062

25 cot^{2} (x) - 1 = 0

\frac{3}{2} = - \frac{1}{2} \cdot sin (θ)

sin (θ) = 0.27, 0 \leq θ < 2 π

What is the general solution for sin(t)= 1/2 ,0<= t< pi/2 ?
The general solution for sin(t)= 1/2 ,0<= t< pi/2 is t= pi/6