What is the general solution for sec^2(x)-1*sec^2(x)=sin^2(x) ?

The general solution for sec^2(x)-1*sec^2(x)=sin^2(x) is x=2pin,x=pi+2pin

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sec^2(x)-1*sec^2(x)=sin^2(x)

sec^{2} (x) - 1 \cdot sec^{2} (x) = sin^{2} (x)

x = 2 πn, x = π + 2 πn

Degrees

x = 0^{\circ} + 36 0^{\circ} n, x = 18 0^{\circ} + 36 0^{\circ} n

Solution steps

sec^{2} (x) - 1 \cdot sec^{2} (x) = sin^{2} (x)

sec^{2} (x) - 1 \cdot sec^{2} (x) = 0

sec^{2} (x) - 1 \cdot sec^{2} (x)

Add similar elements:

sec^{2} (x) - 1 \cdot sec^{2} (x) = 0

= 0

0 = sin^{2} (x)

Switch sides

sin^{2} (x) = 0

Apply rule

x^{n} = 0 \Rightarrow x = 0

sin (x) = 0

General solutions for

sin (x) = 0

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = 0 + 2 πn, x = π + 2 πn

x = 0 + 2 πn, x = π + 2 πn

Solve

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn, x = π + 2 πn

\frac{17}{8} sin (82 x + 1.326) = 0

- 1 - 2 cos (x) = - cos (x)

x, arctan (\frac{y}{x}) = 45

cos (H) = 0.3648447229

θ, cos (\frac{θ}{2} + 3 0^{\circ}) = sin (θ)

What is the general solution for sec^2(x)-1*sec^2(x)=sin^2(x) ?
The general solution for sec^2(x)-1*sec^2(x)=sin^2(x) is x=2pin,x=pi+2pin