What is the general solution for -1+sin(x)=-1 ?

The general solution for -1+sin(x)=-1 is x=2pin,x=pi+2pin

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-1+sin(x)=-1

- 1 + sin (x) = - 1

x = 2 πn, x = π + 2 πn

Degrees

x = 0^{\circ} + 36 0^{\circ} n, x = 18 0^{\circ} + 36 0^{\circ} n

Solution steps

- 1 + sin (x) = - 1

Add

1

to both sides

- 1 + sin (x) + 1 = - 1 + 1

Simplify

sin (x) = 0

General solutions for

sin (x) = 0

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = 0 + 2 πn, x = π + 2 πn

x = 0 + 2 πn, x = π + 2 πn

Solve

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn, x = π + 2 πn

\frac{2}{2} = sin (θ)

cos (a) = 1, 8 b = 1, 5 c = 23

sin (θ) cos (θ) = \frac{2 3}{5}

tan (2 5^{\circ}) = cot (2 x + 5)

sin (a) = 0.4

What is the general solution for -1+sin(x)=-1 ?
The general solution for -1+sin(x)=-1 is x=2pin,x=pi+2pin