What is the general solution for arccos(3x)=1 ?

The general solution for arccos(3x)=1 is x=(cos(1))/3

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arccos(3x)=1

arccos (3 x) = 1

x = \frac{cos ( 1 )}{3}

Solution steps

arccos (3 x) = 1

Apply trig inverse properties

arccos (3 x) = 1

arccos (x) = a \Rightarrow x = cos (a)

3 x = cos (1)

3 x = cos (1)

Solve

3 x = cos (1) : x = \frac{cos ( 1 )}{3}

3 x = cos (1)

Divide both sides by

3

3 x = cos (1)

Divide both sides by

3

\frac{3 x}{3} = \frac{cos ( 1 )}{3}

Simplify

x = \frac{cos ( 1 )}{3}

x = \frac{cos ( 1 )}{3}

x = \frac{cos ( 1 )}{3}

sin (θ) - cos (θ) = \frac{3}{2}, θ [\frac{3 π}{2}, 2 π]

1 6^{s i n (x)} = 8^{c s c (x)}

tan^{2} (x) - 6 tan (x) - 7 = 0

3 sin (2 x) = 2, 0 \leq x \leq π

cos (θ) = \frac{2}{2.24}

What is the general solution for arccos(3x)=1 ?
The general solution for arccos(3x)=1 is x=(cos(1))/3