What is the general solution for sin(A)= 4/5 ,sin(2A) ?

The general solution for sin(A)= 4/5 ,sin(2A) is No Solution for A\in\mathbb{R}

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sin(A)= 4/5 ,sin(2A)

sin (A) = \frac{4}{5}, sin (2 A)

No Solution for A \in R

Solution steps

sin (A) = \frac{4}{5}, sin (2 A)

Apply trig inverse properties

sin (A) = \frac{4}{5}

General solutions for

sin (A) = \frac{4}{5}

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

A = arcsin (\frac{4}{5}) + 2 πn, A = π - arcsin (\frac{4}{5}) + 2 πn

A = arcsin (\frac{4}{5}) + 2 πn, A = π - arcsin (\frac{4}{5}) + 2 πn

Solutions for the range

sin (2 A)

No Solution for A \in R

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2 sin^{2} (x) + cos (x) - 3 = 0

cot (x) cos^{2} (x) = 2 cot (x), 0 \leq x \leq 2 π

What is the general solution for sin(A)= 4/5 ,sin(2A) ?
The general solution for sin(A)= 4/5 ,sin(2A) is No Solution for A\in\mathbb{R}