What is the general solution for sin(θ)=0.35 ?

The general solution for sin(θ)=0.35 is θ=0.35757…+2pin,θ=pi-0.35757…+2pin

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sin(θ)=0.35

sin (θ) = 0.35

θ = 0.35757 \dots + 2 πn, θ = π - 0.35757 \dots + 2 πn

Degrees

θ = 20.48731 \dots^{\circ} + 36 0^{\circ} n, θ = 159.51268 \dots^{\circ} + 36 0^{\circ} n

Solution steps

sin (θ) = 0.35

Apply trig inverse properties

sin (θ) = 0.35

General solutions for

sin (θ) = 0.35

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

θ = arcsin (0.35) + 2 πn, θ = π - arcsin (0.35) + 2 πn

θ = arcsin (0.35) + 2 πn, θ = π - arcsin (0.35) + 2 πn

Show solutions in decimal form

θ = 0.35757 \dots + 2 πn, θ = π - 0.35757 \dots + 2 πn

sin (θ) = 0.07

9 sin^{2} (x) tan (x) = 16 tan (x)

3 sin (2 x) = 5 cos^{2} (2 x) - 1

sin (x) = 2, sin^{2} (x) = 0

cos (θ) = - 2

What is the general solution for sin(θ)=0.35 ?
The general solution for sin(θ)=0.35 is θ=0.35757…+2pin,θ=pi-0.35757…+2pin