What is the general solution for 5cos(c)+sqrt(23)=0 ?

The general solution for 5cos(c)+sqrt(23)=0 is c=2.85483…+2pin,c=-2.85483…+2pin

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5cos(c)+sqrt(23)=0

5 cos (c) + 23 = 0

c = 2.85483 \dots + 2 πn, c = - 2.85483 \dots + 2 πn

Degrees

c = 163.57005 \dots^{\circ} + 36 0^{\circ} n, c = - 163.57005 \dots^{\circ} + 36 0^{\circ} n

Solution steps

5 cos (c) + 23 = 0

Move

23

to the right side

5 cos (c) + 23 = 0

Subtract

23

from both sides

5 cos (c) + 23 - 23 = 0 - 23

Simplify

5 cos (c) = - 23

5 cos (c) = - 23

Divide both sides by

5

5 cos (c) = - 23

Divide both sides by

5

\frac{5 cos ( c )}{5} = \frac{- 23}{5}

Simplify

cos (c) = - \frac{23}{5}

cos (c) = - \frac{23}{5}

Apply trig inverse properties

cos (c) = - \frac{23}{5}

General solutions for

cos (c) = - \frac{23}{5}

cos (x) = - a \Rightarrow x = arccos (- a) + 2 πn, x = - arccos (- a) + 2 πn

c = arccos (- \frac{23}{5}) + 2 πn, c = - arccos (- \frac{23}{5}) + 2 πn

c = arccos (- \frac{23}{5}) + 2 πn, c = - arccos (- \frac{23}{5}) + 2 πn

Show solutions in decimal form

c = 2.85483 \dots + 2 πn, c = - 2.85483 \dots + 2 πn

cos (2 θ) = - \frac{28}{53}

cos (θ) = \frac{( 1 )}{( 2 )}

csc (x) (cos^{2} (x) + 2) = 0

cos (x - \frac{3}{2} π) = - \frac{2}{2}

tan (2 θ) = 0.5

What is the general solution for 5cos(c)+sqrt(23)=0 ?
The general solution for 5cos(c)+sqrt(23)=0 is c=2.85483…+2pin,c=-2.85483…+2pin