What is the general solution for cos(a)= 9/41 ?

The general solution for cos(a)= 9/41 is a=1.34948…+2pin,a=2pi-1.34948…+2pin

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cos(a)= 9/41

cos (a) = \frac{9}{41}

a = 1.34948 \dots + 2 πn, a = 2 π - 1.34948 \dots + 2 πn

Degrees

a = 77.31961 \dots^{\circ} + 36 0^{\circ} n, a = 282.68038 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (a) = \frac{9}{41}

Apply trig inverse properties

cos (a) = \frac{9}{41}

General solutions for

cos (a) = \frac{9}{41}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

a = arccos (\frac{9}{41}) + 2 πn, a = 2 π - arccos (\frac{9}{41}) + 2 πn

a = arccos (\frac{9}{41}) + 2 πn, a = 2 π - arccos (\frac{9}{41}) + 2 πn

Show solutions in decimal form

a = 1.34948 \dots + 2 πn, a = 2 π - 1.34948 \dots + 2 πn

sin^{2} (θ) - 2 = cos^{2} (θ)

cos (x) = 0, 88

21 = 24 + 8 cos (\frac{π t}{6})

cos (\frac{5}{2} x) = 0

sin (5 x) = sin (7 x)

What is the general solution for cos(a)= 9/41 ?
The general solution for cos(a)= 9/41 is a=1.34948…+2pin,a=2pi-1.34948…+2pin