What is the general solution for 2=2-picos(t) ?

The general solution for 2=2-picos(t) is t= pi/2+2pin,t=(3pi)/2+2pin

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2=2-picos(t)

2 = 2 - π cos (t)

t = \frac{π}{2} + 2 πn, t = \frac{3 π}{2} + 2 πn

Degrees

t = 9 0^{\circ} + 36 0^{\circ} n, t = 27 0^{\circ} + 36 0^{\circ} n

Solution steps

2 = 2 - π cos (t)

Switch sides

2 - π cos (t) = 2

Subtract

2

from both sides

2 - π cos (t) - 2 = 2 - 2

Simplify

- π cos (t) = 0

Divide both sides by

- π

- π cos (t) = 0

Divide both sides by

- π

\frac{- π cos ( t )}{- π} = \frac{0}{- π}

Simplify

cos (t) = 0

cos (t) = 0

General solutions for

cos (t) = 0

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

t = \frac{π}{2} + 2 πn, t = \frac{3 π}{2} + 2 πn

t = \frac{π}{2} + 2 πn, t = \frac{3 π}{2} + 2 πn

a, 45 = arctanh (\frac{a}{b})

x, sec (x) = 3

cot (θ - 3 0^{\circ}) = \frac{1}{3}

(cot (x) - 3) (csc (x) + 2) = 0

sin (x) = \frac{7}{9.4}

What is the general solution for 2=2-picos(t) ?
The general solution for 2=2-picos(t) is t= pi/2+2pin,t=(3pi)/2+2pin