What is the general solution for tan(θ)=-12/5 , pi/2 <= θ<= pi ?

The general solution for tan(θ)=-12/5 , pi/2 <= θ<= pi is θ=-1.17600…+pi

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tan(θ)=-12/5 , pi/2 <= θ<= pi

tan (θ) = - \frac{12}{5}, \frac{π}{2} \leq θ \leq π

θ = - 1.17600 \dots + π

Degrees

θ = 112.61986 \dots^{\circ}

Solution steps

tan (θ) = - \frac{12}{5}, \frac{π}{2} \leq θ \leq π

Apply trig inverse properties

tan (θ) = - \frac{12}{5}

General solutions for

tan (θ) = - \frac{12}{5}

tan (x) = - a \Rightarrow x = arctan (- a) + πn

θ = arctan (- \frac{12}{5}) + πn

θ = arctan (- \frac{12}{5}) + πn

Solutions for the range

\frac{π}{2} \leq θ \leq π

θ = - arctan (\frac{12}{5}) + π

Show solutions in decimal form

θ = - 1.17600 \dots + π

cos (x) = sin (2 x + \frac{π}{2}), 0 \leq x \leq 2 π

cos (x) = - 0.397

sin (2 x) cos (x) + cos (2 x) sin (x) = \frac{3}{2}

cos (x) = \frac{5 2}{10}

4 tan (x) + 4 = 0

What is the general solution for tan(θ)=-12/5 , pi/2 <= θ<= pi ?
The general solution for tan(θ)=-12/5 , pi/2 <= θ<= pi is θ=-1.17600…+pi