What is the general solution for cos(θ)=(2sqrt(13))/(13) ?

The general solution for cos(θ)=(2sqrt(13))/(13) is θ=0.98279…+2pin,θ=2pi-0.98279…+2pin

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cos(θ)=(2sqrt(13))/(13)

cos (θ) = \frac{2 13}{13}

θ = 0.98279 \dots + 2 πn, θ = 2 π - 0.98279 \dots + 2 πn

Degrees

θ = 56.30993 \dots^{\circ} + 36 0^{\circ} n, θ = 303.69006 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (θ) = \frac{2 13}{13}

Apply trig inverse properties

cos (θ) = \frac{2 13}{13}

General solutions for

cos (θ) = \frac{2 13}{13}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{2 13}{13}) + 2 πn, θ = 2 π - arccos (\frac{2 13}{13}) + 2 πn

θ = arccos (\frac{2 13}{13}) + 2 πn, θ = 2 π - arccos (\frac{2 13}{13}) + 2 πn

Show solutions in decimal form

θ = 0.98279 \dots + 2 πn, θ = 2 π - 0.98279 \dots + 2 πn

cos^{2} (A) + 2 = 3 cos (A)

sin (θ) = \frac{- 5}{6}

\frac{sin ( x )}{16} = \frac{sin ( 3 1 ^{\circ} )}{12}

sin (A) = \frac{2}{3}

3 cos (2 x + 1) = 2

What is the general solution for cos(θ)=(2sqrt(13))/(13) ?
The general solution for cos(θ)=(2sqrt(13))/(13) is θ=0.98279…+2pin,θ=2pi-0.98279…+2pin