What is the general solution for sin(b)= 1/(sqrt(3)) ?

The general solution for sin(b)= 1/(sqrt(3)) is b=0.61547…+2pin,b=pi-0.61547…+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(b)= 1/(sqrt(3))

sin (b) = \frac{1}{3}

b = 0.61547 \dots + 2 πn, b = π - 0.61547 \dots + 2 πn

Radians

b = 0.61547 \dots + 6.28318 \dots n, b = π - 0.61547 \dots + 6.28318 \dots n

Solution steps

sin (b) = \frac{1}{3}

Simplify

\frac{1}{3} : \frac{3}{3}

\frac{1}{3}

Multiply by the conjugate

\frac{3}{3}

= \frac{1 \cdot 3}{3 3}

1 \cdot 3 = 3

33 = 3

33

Apply radical rule:

a a = a

33 = 3

= 3

= \frac{3}{3}

sin (b) = \frac{3}{3}

Apply trig inverse properties

sin (b) = \frac{3}{3}

General solutions for

sin (b) = \frac{3}{3}

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

b = arcsin (\frac{3}{3}) + 2 πn, b = π - arcsin (\frac{3}{3}) + 2 πn

b = arcsin (\frac{3}{3}) + 2 πn, b = π - arcsin (\frac{3}{3}) + 2 πn

Show solutions in decimal form

b = 0.61547 \dots + 2 πn, b = π - 0.61547 \dots + 2 πn

35 + 53 sin (2 T - 31.9) = 0

cos (2 x) = - 12

2 cos^{2} (x) + 3 cos (x) = 1

sin (θ) = - \frac{5}{6}, sec (θ)

sin (x) = \frac{1}{3}, cos (x)

What is the general solution for sin(b)= 1/(sqrt(3)) ?
The general solution for sin(b)= 1/(sqrt(3)) is b=0.61547…+2pin,b=pi-0.61547…+2pin