What is the general solution for cos(b)= 12/37 ?

The general solution for cos(b)= 12/37 is b=1.24049…+2pin,b=2pi-1.24049…+2pin

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cos(b)= 12/37

cos (b) = \frac{12}{37}

b = 1.24049 \dots + 2 πn, b = 2 π - 1.24049 \dots + 2 πn

Degrees

b = 71.07535 \dots^{\circ} + 36 0^{\circ} n, b = 288.92464 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (b) = \frac{12}{37}

Apply trig inverse properties

cos (b) = \frac{12}{37}

General solutions for

cos (b) = \frac{12}{37}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

b = arccos (\frac{12}{37}) + 2 πn, b = 2 π - arccos (\frac{12}{37}) + 2 πn

b = arccos (\frac{12}{37}) + 2 πn, b = 2 π - arccos (\frac{12}{37}) + 2 πn

Show solutions in decimal form

b = 1.24049 \dots + 2 πn, b = 2 π - 1.24049 \dots + 2 πn

27 (sin (2 t) cos (t) - (sin (t))^{3}) = 0

2 cos^{2} (x) + cos^{2} (x) = 0

cos (t) = \frac{1}{3}

(1 - sin (x)) (\frac{( 1 + sin ( x ) )}{2 cos ( x )}) = 1

\frac{9.03}{sin ( 4 0 ^{\circ} )} = \frac{10}{sin ( x )}

What is the general solution for cos(b)= 12/37 ?
The general solution for cos(b)= 12/37 is b=1.24049…+2pin,b=2pi-1.24049…+2pin