What is the general solution for solvefor θ,2cot(θ)-1=0 ?

The general solution for solvefor θ,2cot(θ)-1=0 is θ=1.10714…+pin

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solvefor θ,2cot(θ)-1=0

solve for

θ, 2 cot (θ) - 1 = 0

θ = 1.10714 \dots + πn

Degrees

θ = 63.43494 \dots^{\circ} + 18 0^{\circ} n

Solution steps

2 cot (θ) - 1 = 0

Move

1

to the right side

2 cot (θ) - 1 = 0

Add

1

to both sides

2 cot (θ) - 1 + 1 = 0 + 1

Simplify

2 cot (θ) = 1

2 cot (θ) = 1

Divide both sides by

2

2 cot (θ) = 1

Divide both sides by

2

\frac{2 cot ( θ )}{2} = \frac{1}{2}

Simplify

cot (θ) = \frac{1}{2}

cot (θ) = \frac{1}{2}

Apply trig inverse properties

cot (θ) = \frac{1}{2}

General solutions for

cot (θ) = \frac{1}{2}

cot (x) = a \Rightarrow x = arccot (a) + πn

θ = arccot (\frac{1}{2}) + πn

θ = arccot (\frac{1}{2}) + πn

Show solutions in decimal form

θ = 1.10714 \dots + πn

cos (x) = \frac{a}{b}

sin^{2} (θ) - sin (θ) - 12 = 0

2 cos^{2} (x) - sin (- x) - 1 = 0

589 \cdot sin (4 5^{\circ}) = 443 \cdot sin (x)

cos (θ) = 0.7609

What is the general solution for solvefor θ,2cot(θ)-1=0 ?
The general solution for solvefor θ,2cot(θ)-1=0 is θ=1.10714…+pin