What is the general solution for cos(x)= a/b ?

The general solution for cos(x)= a/b is x=arccos(a/b)+2pin,x=-arccos(a/b)+2pin

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cos(x)= a/b

cos (x) = \frac{a}{b}

x = arccos (\frac{a}{b}) + 2 πn, x = - arccos (\frac{a}{b}) + 2 πn

Solution steps

cos (x) = \frac{a}{b}

Apply trig inverse properties

cos (x) = \frac{a}{b}

General solutions for

cos (x) = \frac{a}{b}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = - arccos (a) + 2 πn

x = arccos (\frac{a}{b}) + 2 πn, x = - arccos (\frac{a}{b}) + 2 πn

x = arccos (\frac{a}{b}) + 2 πn, x = - arccos (\frac{a}{b}) + 2 πn

sin^{2} (θ) - sin (θ) - 12 = 0

2 cos^{2} (x) - sin (- x) - 1 = 0

589 \cdot sin (4 5^{\circ}) = 443 \cdot sin (x)

cos (θ) = 0.7609

sin (x) = \frac{3}{2}, 0 \leq x < 2 π

What is the general solution for cos(x)= a/b ?
The general solution for cos(x)= a/b is x=arccos(a/b)+2pin,x=-arccos(a/b)+2pin