What is the general solution for 3sin(2x)-2sin(2x)=0 ?

The general solution for 3sin(2x)-2sin(2x)=0 is x=pin,x= pi/2+pin

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3sin(2x)-2sin(2x)=0

3 sin (2 x) - 2 sin (2 x) = 0

x = πn, x = \frac{π}{2} + πn

Degrees

x = 0^{\circ} + 18 0^{\circ} n, x = 9 0^{\circ} + 18 0^{\circ} n

Solution steps

3 sin (2 x) - 2 sin (2 x) = 0

Simplify

3 sin (2 x) - 2 sin (2 x) : sin (2 x)

3 sin (2 x) - 2 sin (2 x)

Add similar elements:

3 sin (2 x) - 2 sin (2 x) = sin (2 x)

= sin (2 x)

sin (2 x) = 0

General solutions for

sin (2 x) = 0

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

2 x = 0 + 2 πn, 2 x = π + 2 πn

2 x = 0 + 2 πn, 2 x = π + 2 πn

Solve

2 x = 0 + 2 πn : x = πn

2 x = 0 + 2 πn

0 + 2 πn = 2 πn

2 x = 2 πn

Divide both sides by

2

2 x = 2 πn

Divide both sides by

2

\frac{2 x}{2} = \frac{2 πn}{2}

Simplify

x = πn

x = πn

Solve

2 x = π + 2 πn : x = \frac{π}{2} + πn

2 x = π + 2 πn

Divide both sides by

2

2 x = π + 2 πn

Divide both sides by

2

\frac{2 x}{2} = \frac{π}{2} + \frac{2 πn}{2}

Simplify

x = \frac{π}{2} + πn

x = \frac{π}{2} + πn

x = πn, x = \frac{π}{2} + πn

2 cos (4 x) + 5 = 6

cos (2 θ) = - \frac{3}{2}, 0 \leq θ \leq 2 π

2 cos^{2} (a) = 1 + cos (12 0^{\circ})

cos (x) = \frac{11}{17 \cdot 38}

\frac{sin ( 9 0 ^{\circ} )}{5.8} = \frac{sin ( x )}{5}

What is the general solution for 3sin(2x)-2sin(2x)=0 ?
The general solution for 3sin(2x)-2sin(2x)=0 is x=pin,x= pi/2+pin