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شائع علم المثلثات >

cos^4(x)=1-sin^4(x)

الحلّ

cos^{4} (x) = 1 - sin^{4} (x)

الحلّ

x = 2 πn, x = π + 2 πn, x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

درجات

x = 0^{\circ} + 36 0^{\circ} n, x = 18 0^{\circ} + 36 0^{\circ} n, x = 9 0^{\circ} + 36 0^{\circ} n, x = 27 0^{\circ} + 36 0^{\circ} n

خطوات الحلّ

cos^{4} (x) = 1 - sin^{4} (x)

من الطرفين

1 - sin^{4} (x)

اطرح

cos^{4} (x) - 1 + sin^{4} (x) = 0

a^{b} = a^{2} a^{b - 2} :

فعّل قانون القوى

- 1 + cos^{4} (x) + sin^{2} (x) sin^{2} (x) = 0

Rewrite using trig identities

- 1 + cos^{4} (x) + sin^{2} (x) sin^{2} (x)

cos^{2} (x) + sin^{2} (x) = 1

:فعّل نطريّة فيتاغوروس

sin^{2} (x) = 1 - cos^{2} (x)

= - 1 + cos^{4} (x) + (1 - cos^{2} (x)) (1 - cos^{2} (x))

- 1 + cos^{4} (x) + (1 - cos^{2} (x)) (1 - cos^{2} (x))

بسّط:

2 cos^{4} (x) - 2 cos^{2} (x)

- 1 + cos^{4} (x) + (1 - cos^{2} (x)) (1 - cos^{2} (x))

(1 - cos^{2} (x)) (1 - cos^{2} (x)) = (1 - cos^{2} (x))^{2}

(1 - cos^{2} (x)) (1 - cos^{2} (x))

a^{b} \cdot a^{c} = a^{b + c}

:فعّل قانون القوى

(1 - cos^{2} (x)) (1 - cos^{2} (x)) = (1 - cos^{2} (x))^{1 + 1}

= (1 - cos^{2} (x))^{1 + 1}

1 + 1 = 2 :

اجمع الأعداد

= (1 - cos^{2} (x))^{2}

= - 1 + cos^{4} (x) + (- cos^{2} (x) + 1)^{2}

(1 - cos^{2} (x))^{2} : 1 - 2 cos^{2} (x) + cos^{4} (x)

(a - b)^{2} = a^{2} - 2 ab + b^{2}

:فعّل صيغة الضرب المختصر

a = 1, b = cos^{2} (x)

= 1^{2} - 2 \cdot 1 \cdot cos^{2} (x) + (cos^{2} (x))^{2}

1^{2} - 2 \cdot 1 \cdot cos^{2} (x) + (cos^{2} (x))^{2}

بسّط:

1 - 2 cos^{2} (x) + cos^{4} (x)

1^{2} - 2 \cdot 1 \cdot cos^{2} (x) + (cos^{2} (x))^{2}

1^{a} = 1

فعّل القانون

1^{2} = 1

= 1 - 2 \cdot 1 \cdot cos^{2} (x) + (cos^{2} (x))^{2}

2 \cdot 1 \cdot cos^{2} (x) = 2 cos^{2} (x)

2 \cdot 1 \cdot cos^{2} (x)

2 \cdot 1 = 2 :

اضرب الأعداد

= 2 cos^{2} (x)

(cos^{2} (x))^{2} = cos^{4} (x)

(cos^{2} (x))^{2}

(a^{b})^{c} = a^{b c}

:فعّل قانون القوى

= cos^{2 \cdot 2} (x)

2 \cdot 2 = 4 :

اضرب الأعداد

= cos^{4} (x)

= 1 - 2 cos^{2} (x) + cos^{4} (x)

= 1 - 2 cos^{2} (x) + cos^{4} (x)

= - 1 + cos^{4} (x) + 1 - 2 cos^{2} (x) + cos^{4} (x)

- 1 + cos^{4} (x) + 1 - 2 cos^{2} (x) + cos^{4} (x)

بسّط:

2 cos^{4} (x) - 2 cos^{2} (x)

- 1 + cos^{4} (x) + 1 - 2 cos^{2} (x) + cos^{4} (x)

جمّع التعابير المتشابهة

= cos^{4} (x) - 2 cos^{2} (x) + cos^{4} (x) - 1 + 1

cos^{4} (x) + cos^{4} (x) = 2 cos^{4} (x) :

اجمع العناصر المتشابهة

= 2 cos^{4} (x) - 2 cos^{2} (x) - 1 + 1

- 1 + 1 = 0

= 2 cos^{4} (x) - 2 cos^{2} (x)

= 2 cos^{4} (x) - 2 cos^{2} (x)

= 2 cos^{4} (x) - 2 cos^{2} (x)

- 2 cos^{2} (x) + 2 cos^{4} (x) = 0

بالاستعانة بطريقة التعويض

- 2 cos^{2} (x) + 2 cos^{4} (x) = 0

cos (x) = u :

على افتراض أنّ

- 2 u^{2} + 2 u^{4} = 0

- 2 u^{2} + 2 u^{4} = 0 : u = 1, u = - 1, u = 0

- 2 u^{2} + 2 u^{4} = 0

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

اكتب بالصورة الاعتياديّة

2 u^{4} - 2 u^{2} = 0

v^{2} = u^{4}

وكذلك

v = u^{2}

اكتب المعادلة مجددًا، بحيث أنّ

2 v^{2} - 2 v = 0

2 v^{2} - 2 v = 0

حلّ:

v = 1, v = 0

2 v^{2} - 2 v = 0

حلّ بالاستعانة بالصيغة التربيعيّة

2 v^{2} - 2 v = 0

الصيغة لحلّ المعادلة التربيعيّة

a = 2, b = - 2, c = 0

لـ

v_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

v_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 2)^{2} - 4 \cdot 2 \cdot 0 = 2

(- 2)^{2} - 4 \cdot 2 \cdot 0

زوجيّ n

إذا تحقّق أنّ

, (- a)^{n} = a^{n}

:فعّل قانون القوى

(- 2)^{2} = 2^{2}

= 2^{2} - 4 \cdot 2 \cdot 0

0 \cdot a = 0

فعّل القانون

= 2^{2} - 0

2^{2} - 0 = 2^{2}

= 2^{2}

a \geq 0

بافتراض أنّ

n a^{n} = a

:فعّل قانون الجذور

= 2

v_{1, 2} = \frac{- ( - 2 ) \pm 2}{2 \cdot 2}

Separate the solutions

v_{1} = \frac{- ( - 2 ) + 2}{2 \cdot 2}, v_{2} = \frac{- ( - 2 ) - 2}{2 \cdot 2}

v = \frac{- ( - 2 ) + 2}{2 \cdot 2} : 1

\frac{- ( - 2 ) + 2}{2 \cdot 2}

- (- a) = a

فعّل القانون

= \frac{2 + 2}{2 \cdot 2}

2 + 2 = 4 :

اجمع الأعداد

= \frac{4}{2 \cdot 2}

2 \cdot 2 = 4 :

اضرب الأعداد

= \frac{4}{4}

\frac{a}{a} = 1

فعّل القانون

= 1

v = \frac{- ( - 2 ) - 2}{2 \cdot 2} : 0

\frac{- ( - 2 ) - 2}{2 \cdot 2}

- (- a) = a

فعّل القانون

= \frac{2 - 2}{2 \cdot 2}

2 - 2 = 0 :

اطرح الأعداد

= \frac{0}{2 \cdot 2}

2 \cdot 2 = 4 :

اضرب الأعداد

= \frac{0}{4}

\frac{0}{a} = 0, a \neq = 0

فعّل القانون

= 0

حلول المعادلة التربيعيّة هي

v = 1, v = 0

v = 1, v = 0

Substitute back

v = u^{2},

solve for

u

u^{2} = 1

حلّ:

u = 1, u = - 1

u^{2} = 1

x = f (a), - f (a)

الحلول هي

x^{2} = f (a)

لـ

u = 1, u = - 1

1 = 1

1

1 = 1

فعّل القانون

= 1

- 1 = - 1

- 1

1 = 1

فعّل القانون

= - 1

u = 1, u = - 1

u^{2} = 0

حلّ:

u = 0

u^{2} = 0

x^{n} = 0 \Rightarrow x = 0

فعّل القانون

u = 0

The solutions are

u = 1, u = - 1, u = 0

u = cos (x)

استبدل مجددًا

cos (x) = 1, cos (x) = - 1, cos (x) = 0

cos (x) = 1, cos (x) = - 1, cos (x) = 0

cos (x) = 1 : x = 2 πn

cos (x) = 1

cos (x) = 1 :

حلول عامّة لـ

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = 0 + 2 πn

x = 0 + 2 πn

x = 0 + 2 πn

حلّ:

x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn

cos (x) = - 1 : x = π + 2 πn

cos (x) = - 1

cos (x) = - 1 :

حلول عامّة لـ

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = π + 2 πn

x = π + 2 πn

cos (x) = 0 : x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

cos (x) = 0

cos (x) = 0 :

حلول عامّة لـ

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

وحّد الحلول

x = 2 πn, x = π + 2 πn, x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

رسم

أمثلة شائعة

sec^2(x)+cot^2(x)=csc^2(x)

sec^{2} (x) + cot^{2} (x) = csc^{2} (x)

((sin^2(x)))/((1-cos(x)))=1.23

\frac{( sin ^{2} ( x ) )}{( 1 - cos ( x ) )} = 1.23

sin(2x)=cos(8x)

sin (2 x) = cos (8 x)

8=sin(x)

8 = sin (x)

-2cot(x)+csc^2(x)=0

- 2 cot (x) + csc^{2} (x) = 0