What is the general solution for cos(t)= 24/25 ?

The general solution for cos(t)= 24/25 is t=0.28379…+2pin,t=2pi-0.28379…+2pin

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cos(t)= 24/25

cos (t) = \frac{24}{25}

t = 0.28379 \dots + 2 πn, t = 2 π - 0.28379 \dots + 2 πn

Degrees

t = 16.26020 \dots^{\circ} + 36 0^{\circ} n, t = 343.73979 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (t) = \frac{24}{25}

Apply trig inverse properties

cos (t) = \frac{24}{25}

General solutions for

cos (t) = \frac{24}{25}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

t = arccos (\frac{24}{25}) + 2 πn, t = 2 π - arccos (\frac{24}{25}) + 2 πn

t = arccos (\frac{24}{25}) + 2 πn, t = 2 π - arccos (\frac{24}{25}) + 2 πn

Show solutions in decimal form

t = 0.28379 \dots + 2 πn, t = 2 π - 0.28379 \dots + 2 πn

sec^{2} (t) + 2 sec (t) = 0

sin (27 0^{\circ} + x) - cos (18 0^{\circ} - x) = - sin (x)

9 cos (3 x) = 0

16 (l) cos (θ) = 5 sin (2 θ) (2 l)

∣ sin (x) ∣ = \frac{2}{π}

What is the general solution for cos(t)= 24/25 ?
The general solution for cos(t)= 24/25 is t=0.28379…+2pin,t=2pi-0.28379…+2pin