解答
9.8sin(x)−1.96cos(x)=8.54
解答
x=2.31438…+2πn,x=1.22199…+2πn
+1
度数
x=132.60472…∘+360∘n,x=70.01513…∘+360∘n求解步骤
9.8sin(x)−1.96cos(x)=8.54
两边加上 1.96cos(x)9.8sin(x)=8.54+1.96cos(x)
两边进行平方(9.8sin(x))2=(8.54+1.96cos(x))2
两边减去 (8.54+1.96cos(x))296.04sin2(x)−72.9316−33.4768cos(x)−3.8416cos2(x)=0
使用三角恒等式改写
−72.9316−3.8416cos2(x)−33.4768cos(x)+96.04sin2(x)
使用毕达哥拉斯恒等式: cos2(x)+sin2(x)=1sin2(x)=1−cos2(x)=−72.9316−3.8416cos2(x)−33.4768cos(x)+96.04(1−cos2(x))
化简 −72.9316−3.8416cos2(x)−33.4768cos(x)+96.04(1−cos2(x)):−99.8816cos2(x)−33.4768cos(x)+23.1084
−72.9316−3.8416cos2(x)−33.4768cos(x)+96.04(1−cos2(x))
乘开 96.04(1−cos2(x)):96.04−96.04cos2(x)
96.04(1−cos2(x))
使用分配律: a(b−c)=ab−aca=96.04,b=1,c=cos2(x)=96.04⋅1−96.04cos2(x)
=1⋅96.04−96.04cos2(x)
数字相乘:1⋅96.04=96.04=96.04−96.04cos2(x)
=−72.9316−3.8416cos2(x)−33.4768cos(x)+96.04−96.04cos2(x)
化简 −72.9316−3.8416cos2(x)−33.4768cos(x)+96.04−96.04cos2(x):−99.8816cos2(x)−33.4768cos(x)+23.1084
−72.9316−3.8416cos2(x)−33.4768cos(x)+96.04−96.04cos2(x)
对同类项分组=−3.8416cos2(x)−33.4768cos(x)−96.04cos2(x)−72.9316+96.04
同类项相加:−3.8416cos2(x)−96.04cos2(x)=−99.8816cos2(x)=−99.8816cos2(x)−33.4768cos(x)−72.9316+96.04
数字相加/相减:−72.9316+96.04=23.1084=−99.8816cos2(x)−33.4768cos(x)+23.1084
=−99.8816cos2(x)−33.4768cos(x)+23.1084
=−99.8816cos2(x)−33.4768cos(x)+23.1084
23.1084−33.4768cos(x)−99.8816cos2(x)=0
用替代法求解
23.1084−33.4768cos(x)−99.8816cos2(x)=0
令:cos(x)=u23.1084−33.4768u−99.8816u2=0
23.1084−33.4768u−99.8816u2=0:u=−199.763233.4768+10353.112,u=199.763210353.112−33.4768
23.1084−33.4768u−99.8816u2=0
改写成标准形式 ax2+bx+c=0−99.8816u2−33.4768u+23.1084=0
使用求根公式求解
−99.8816u2−33.4768u+23.1084=0
二次方程求根公式:
若 a=−99.8816,b=−33.4768,c=23.1084u1,2=2(−99.8816)−(−33.4768)±(−33.4768)2−4(−99.8816)⋅23.1084
u1,2=2(−99.8816)−(−33.4768)±(−33.4768)2−4(−99.8816)⋅23.1084
(−33.4768)2−4(−99.8816)⋅23.1084=10353.112
(−33.4768)2−4(−99.8816)⋅23.1084
使用法则 −(−a)=a=(−33.4768)2+4⋅99.8816⋅23.1084
使用指数法则: (−a)n=an,若 n 是偶数(−33.4768)2=33.47682=33.47682+4⋅23.1084⋅99.8816
数字相乘:4⋅99.8816⋅23.1084=9232.41586…=33.47682+9232.41586…
33.47682=1120.69613…=1120.69613…+9232.41586…
数字相加:1120.69613…+9232.41586…=10353.112=10353.112
u1,2=2(−99.8816)−(−33.4768)±10353.112
将解分隔开u1=2(−99.8816)−(−33.4768)+10353.112,u2=2(−99.8816)−(−33.4768)−10353.112
u=2(−99.8816)−(−33.4768)+10353.112:−199.763233.4768+10353.112
2(−99.8816)−(−33.4768)+10353.112
去除括号: (−a)=−a,−(−a)=a=−2⋅99.881633.4768+10353.112
数字相乘:2⋅99.8816=199.7632=−199.763233.4768+10353.112
使用分式法则: −ba=−ba=−199.763233.4768+10353.112
u=2(−99.8816)−(−33.4768)−10353.112:199.763210353.112−33.4768
2(−99.8816)−(−33.4768)−10353.112
去除括号: (−a)=−a,−(−a)=a=−2⋅99.881633.4768−10353.112
数字相乘:2⋅99.8816=199.7632=−199.763233.4768−10353.112
使用分式法则: −b−a=ba33.4768−10353.112=−(10353.112−33.4768)=199.763210353.112−33.4768
二次方程组的解是:u=−199.763233.4768+10353.112,u=199.763210353.112−33.4768
u=cos(x)代回cos(x)=−199.763233.4768+10353.112,cos(x)=199.763210353.112−33.4768
cos(x)=−199.763233.4768+10353.112,cos(x)=199.763210353.112−33.4768
cos(x)=−199.763233.4768+10353.112:x=arccos(−199.763233.4768+10353.112)+2πn,x=−arccos(−199.763233.4768+10353.112)+2πn
cos(x)=−199.763233.4768+10353.112
使用反三角函数性质
cos(x)=−199.763233.4768+10353.112
cos(x)=−199.763233.4768+10353.112的通解cos(x)=−a⇒x=arccos(−a)+2πn,x=−arccos(−a)+2πnx=arccos(−199.763233.4768+10353.112)+2πn,x=−arccos(−199.763233.4768+10353.112)+2πn
x=arccos(−199.763233.4768+10353.112)+2πn,x=−arccos(−199.763233.4768+10353.112)+2πn
cos(x)=199.763210353.112−33.4768:x=arccos(199.763210353.112−33.4768)+2πn,x=2π−arccos(199.763210353.112−33.4768)+2πn
cos(x)=199.763210353.112−33.4768
使用反三角函数性质
cos(x)=199.763210353.112−33.4768
cos(x)=199.763210353.112−33.4768的通解cos(x)=a⇒x=arccos(a)+2πn,x=2π−arccos(a)+2πnx=arccos(199.763210353.112−33.4768)+2πn,x=2π−arccos(199.763210353.112−33.4768)+2πn
x=arccos(199.763210353.112−33.4768)+2πn,x=2π−arccos(199.763210353.112−33.4768)+2πn
合并所有解x=arccos(−199.763233.4768+10353.112)+2πn,x=−arccos(−199.763233.4768+10353.112)+2πn,x=arccos(199.763210353.112−33.4768)+2πn,x=2π−arccos(199.763210353.112−33.4768)+2πn
将解代入原方程进行验证
将它们代入 9.8sin(x)−1.96cos(x)=8.54检验解是否符合
去除与方程不符的解。
检验 arccos(−199.763233.4768+10353.112)+2πn的解:真
arccos(−199.763233.4768+10353.112)+2πn
代入 n=1arccos(−199.763233.4768+10353.112)+2π1
对于 9.8sin(x)−1.96cos(x)=8.54代入x=arccos(−199.763233.4768+10353.112)+2π19.8sin(arccos(−199.763233.4768+10353.112)+2π1)−1.96cos(arccos(−199.763233.4768+10353.112)+2π1)=8.54
整理后得8.54=8.54
⇒真
检验 −arccos(−199.763233.4768+10353.112)+2πn的解:假
−arccos(−199.763233.4768+10353.112)+2πn
代入 n=1−arccos(−199.763233.4768+10353.112)+2π1
对于 9.8sin(x)−1.96cos(x)=8.54代入x=−arccos(−199.763233.4768+10353.112)+2π19.8sin(−arccos(−199.763233.4768+10353.112)+2π1)−1.96cos(−arccos(−199.763233.4768+10353.112)+2π1)=8.54
整理后得−5.88640…=8.54
⇒假
检验 arccos(199.763210353.112−33.4768)+2πn的解:真
arccos(199.763210353.112−33.4768)+2πn
代入 n=1arccos(199.763210353.112−33.4768)+2π1
对于 9.8sin(x)−1.96cos(x)=8.54代入x=arccos(199.763210353.112−33.4768)+2π19.8sin(arccos(199.763210353.112−33.4768)+2π1)−1.96cos(arccos(199.763210353.112−33.4768)+2π1)=8.54
整理后得8.54=8.54
⇒真
检验 2π−arccos(199.763210353.112−33.4768)+2πn的解:假
2π−arccos(199.763210353.112−33.4768)+2πn
代入 n=12π−arccos(199.763210353.112−33.4768)+2π1
对于 9.8sin(x)−1.96cos(x)=8.54代入x=2π−arccos(199.763210353.112−33.4768)+2π19.8sin(2π−arccos(199.763210353.112−33.4768)+2π1)−1.96cos(2π−arccos(199.763210353.112−33.4768)+2π1)=8.54
整理后得−9.87974…=8.54
⇒假
x=arccos(−199.763233.4768+10353.112)+2πn,x=arccos(199.763210353.112−33.4768)+2πn
以小数形式表示解x=2.31438…+2πn,x=1.22199…+2πn