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受欢迎的三角函数 >

[2sin(4x)-1]*[1+tan(x)]=0

解答

[2 sin (4 x) - 1] \cdot [1 + tan (x)] = 0

解答

x = \frac{π}{24} + \frac{πn}{2}, x = \frac{5 π}{24} + \frac{πn}{2}, x = \frac{3 π}{4} + πn

+1

度数

x = 7. 5^{\circ} + 9 0^{\circ} n, x = 37. 5^{\circ} + 9 0^{\circ} n, x = 13 5^{\circ} + 18 0^{\circ} n

求解步骤

[2 sin (4 x) - 1] [1 + tan (x)] = 0

分别求解每个部分

2 sin (4 x) - 1 = 0 or 1 + tan (x) = 0

2 sin (4 x) - 1 = 0 : x = \frac{π}{24} + \frac{πn}{2}, x = \frac{5 π}{24} + \frac{πn}{2}

2 sin (4 x) - 1 = 0

将

1

到右边

2 sin (4 x) - 1 = 0

两边加上

1

2 sin (4 x) - 1 + 1 = 0 + 1

化简

2 sin (4 x) = 1

2 sin (4 x) = 1

两边除以

2

2 sin (4 x) = 1

两边除以

2

\frac{2 sin ( 4 x )}{2} = \frac{1}{2}

化简

sin (4 x) = \frac{1}{2}

sin (4 x) = \frac{1}{2}

sin (4 x) = \frac{1}{2}

的通解

sin (x)

周期表（周期为

2 πn

"）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

4 x = \frac{π}{6} + 2 πn, 4 x = \frac{5 π}{6} + 2 πn

4 x = \frac{π}{6} + 2 πn, 4 x = \frac{5 π}{6} + 2 πn

解

4 x = \frac{π}{6} + 2 πn : x = \frac{π}{24} + \frac{πn}{2}

4 x = \frac{π}{6} + 2 πn

两边除以

4

4 x = \frac{π}{6} + 2 πn

两边除以

4

\frac{4 x}{4} = \frac{\frac{π}{6}}{4} + \frac{2 πn}{4}

化简

\frac{4 x}{4} = \frac{\frac{π}{6}}{4} + \frac{2 πn}{4}

化简

\frac{4 x}{4} : x

\frac{4 x}{4}

数字相除:

\frac{4}{4} = 1

= x

化简

\frac{\frac{π}{6}}{4} + \frac{2 πn}{4} : \frac{π}{24} + \frac{πn}{2}

\frac{\frac{π}{6}}{4} + \frac{2 πn}{4}

\frac{\frac{π}{6}}{4} = \frac{π}{24}

\frac{\frac{π}{6}}{4}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{π}{6 \cdot 4}

数字相乘:

6 \cdot 4 = 24

= \frac{π}{24}

\frac{2 πn}{4} = \frac{πn}{2}

\frac{2 πn}{4}

约分:

2

= \frac{πn}{2}

= \frac{π}{24} + \frac{πn}{2}

x = \frac{π}{24} + \frac{πn}{2}

x = \frac{π}{24} + \frac{πn}{2}

x = \frac{π}{24} + \frac{πn}{2}

解

4 x = \frac{5 π}{6} + 2 πn : x = \frac{5 π}{24} + \frac{πn}{2}

4 x = \frac{5 π}{6} + 2 πn

两边除以

4

4 x = \frac{5 π}{6} + 2 πn

两边除以

4

\frac{4 x}{4} = \frac{\frac{5 π}{6}}{4} + \frac{2 πn}{4}

化简

\frac{4 x}{4} = \frac{\frac{5 π}{6}}{4} + \frac{2 πn}{4}

化简

\frac{4 x}{4} : x

\frac{4 x}{4}

数字相除:

\frac{4}{4} = 1

= x

化简

\frac{\frac{5 π}{6}}{4} + \frac{2 πn}{4} : \frac{5 π}{24} + \frac{πn}{2}

\frac{\frac{5 π}{6}}{4} + \frac{2 πn}{4}

\frac{\frac{5 π}{6}}{4} = \frac{5 π}{24}

\frac{\frac{5 π}{6}}{4}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{5 π}{6 \cdot 4}

数字相乘:

6 \cdot 4 = 24

= \frac{5 π}{24}

\frac{2 πn}{4} = \frac{πn}{2}

\frac{2 πn}{4}

约分:

2

= \frac{πn}{2}

= \frac{5 π}{24} + \frac{πn}{2}

x = \frac{5 π}{24} + \frac{πn}{2}

x = \frac{5 π}{24} + \frac{πn}{2}

x = \frac{5 π}{24} + \frac{πn}{2}

x = \frac{π}{24} + \frac{πn}{2}, x = \frac{5 π}{24} + \frac{πn}{2}

1 + tan (x) = 0 : x = \frac{3 π}{4} + πn

1 + tan (x) = 0

将

1

到右边

1 + tan (x) = 0

两边减去

1

1 + tan (x) - 1 = 0 - 1

化简

tan (x) = - 1

tan (x) = - 1

tan (x) = - 1

的通解

tan (x)

周期表（周期为

πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x = \frac{3 π}{4} + πn

x = \frac{3 π}{4} + πn

合并所有解

x = \frac{π}{24} + \frac{πn}{2}, x = \frac{5 π}{24} + \frac{πn}{2}, x = \frac{3 π}{4} + πn

作图

流行的例子

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