zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的三角函数 >

sqrt(2/pi)*sinh(1)

解答

\frac{2}{π} \cdot sinh (1)

解答

\frac{2 π ( e ^{2} - 1 )}{2 e π}

+1

十进制

0.93767 \dots

求解步骤

\frac{2}{π} sinh (1)

使用三角恒等式改写:

sinh (1) = \frac{e ^{2} - 1}{2 e}

sinh (1)

使用双曲函数恒等式:

sinh (x) = \frac{e ^{x} - e ^{- x}}{2}

= \frac{e ^{1} - e ^{- 1}}{2}

\frac{e ^{1} - e ^{- 1}}{2} = \frac{e ^{2} - 1}{2 e}

\frac{e ^{1} - e ^{- 1}}{2}

使用法则

a^{1} = a

e^{1} = e

= \frac{e - e ^{- 1}}{2}

使用指数法则:

a^{- 1} = \frac{1}{a}

= \frac{e - \frac{1}{e}}{2}

化简

e - \frac{1}{e} : \frac{e ^{2} - 1}{e}

e - \frac{1}{e}

将项转换为分式:

e = \frac{ee}{e}

= \frac{ee}{e} - \frac{1}{e}

因为分母相等，所以合并分式:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{ee - 1}{e}

ee - 1 = e^{2} - 1

ee - 1

ee = e^{2}

ee

使用指数法则:

a^{b} \cdot a^{c} = a^{b + c}

ee = e^{1 + 1}

= e^{1 + 1}

数字相加:

1 + 1 = 2

= e^{2}

= e^{2} - 1

= \frac{e ^{2} - 1}{e}

= \frac{\frac{e ^{2} - 1}{e}}{2}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{e ^{2} - 1}{e 2}

= \frac{e ^{2} - 1}{2 e}

= \frac{2}{π} \frac{e ^{2} - 1}{2 e}

化简

\frac{2}{π} \frac{e ^{2} - 1}{2 e} : \frac{2 π ( e ^{2} - 1 )}{2 e π}

\frac{2}{π} \frac{e ^{2} - 1}{2 e}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( e ^{2} - 1 ) \frac{2}{π}}{2 e}

\frac{2}{π} = \frac{2}{π}

\frac{2}{π}

使用根式运算法则:

n \frac{a}{b} = \frac{n a}{n b},

假定

a \geq 0, b \geq 0

= \frac{2}{π}

= \frac{\frac{2}{π} ( e ^{2} - 1 )}{2 e}

乘

(e^{2} - 1) \frac{2}{π} : \frac{2 ( e ^{2} - 1 )}{π}

(e^{2} - 1) \frac{2}{π}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 ( e ^{2} - 1 )}{π}

= \frac{\frac{2 ( e ^{2} - 1 )}{π}}{2 e}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{2 ( e ^{2} - 1 )}{π \cdot 2 e}

使用根式运算法则:

n a = a^{\frac{1}{n}}

2 = 2^{\frac{1}{2}}

= \frac{2 ^{\frac{1}{2}} ( e ^{2} - 1 )}{2 e π}

使用指数法则:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{2 ^{\frac{1}{2}}}{2 ^{1}} = \frac{1}{2 ^{1 - \frac{1}{2}}}

= \frac{e ^{2} - 1}{2 ^{- \frac{1}{2} + 1} e π}

数字相减:

1 - \frac{1}{2} = \frac{1}{2}

= \frac{e ^{2} - 1}{2 ^{\frac{1}{2}} e π}

使用根式运算法则:

a^{\frac{1}{n}} = n a

2^{\frac{1}{2}} = 2

= \frac{e ^{2} - 1}{2 e π}

\frac{e ^{2} - 1}{2 e π}

有理化:

\frac{2 π ( e ^{2} - 1 )}{2 e π}

\frac{e ^{2} - 1}{2 e π}

乘以共轭根式

\frac{π}{π}

= \frac{( e ^{2} - 1 ) π}{π 2 e π}

π 2 e π = 2 e π

π 2 e π

使用根式运算法则:

a a = a

π π = π

= 2 e π

= \frac{π ( e ^{2} - 1 )}{2 e π}

乘以共轭根式

\frac{2}{2}

= \frac{π ( e ^{2} - 1 ) 2}{2 e π 2}

2 e π 2 = 2 e π

2 e π 2

使用根式运算法则:

a a = a

22 = 2

= 2 e π

= \frac{2 π ( e ^{2} - 1 )}{2 e π}

= \frac{2 π ( e ^{2} - 1 )}{2 e π}

= \frac{2 π ( e ^{2} - 1 )}{2 e π}

流行的例子

sinh (4 x) = \frac{3}{4}

tan(x)+sec(x)=3

tan (x) + sec (x) = 3

2sin(pi/3-x)-1=0

2 sin (\frac{π}{3} - x) - 1 = 0

cos(θ)=-(11)/(sqrt(170))

cos (θ) = - \frac{11}{170}

sin(x)=cos^2(x)-sin^2(x)-1

sin (x) = cos^{2} (x) - sin^{2} (x) - 1