What is the value of (9.3)/(tan(60)) ?

The value of (9.3)/(tan(60)) is (31sqrt(3))/(10)

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(9.3)/(tan(60))

\frac{9.3}{tan ( 6 0 ^{\circ} )}

\frac{31 3}{10}

Decimal Notation

5.36935 \dots

Solution steps

\frac{9.3}{tan ( 6 0 ^{\circ} )}

= \frac{\frac{93}{10}}{tan ( 6 0 ^{\circ} )}

Use the following trivial identity:

tan (6 0^{\circ}) = 3

tan (6 0^{\circ})

tan (x)

periodicity table with

18 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

= 3

= \frac{\frac{93}{10}}{3}

Simplify

\frac{\frac{93}{10}}{3} : \frac{31 3}{10}

\frac{\frac{93}{10}}{3}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{93}{10 3}

Factor

93 : 3 \cdot 31

Factor

93 = 3 \cdot 31

= \frac{3 \cdot 31}{10 3}

Cancel

\frac{3 \cdot 31}{10 3} : \frac{3 \cdot 31}{10}

\frac{3 \cdot 31}{10 3}

Apply radical rule:

3 = 3^{\frac{1}{2}}

= \frac{3 \cdot 31}{10 \cdot 3 ^{\frac{1}{2}}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{3 ^{1}}{3 ^{\frac{1}{2}}} = 3^{1 - \frac{1}{2}}

= \frac{31 \cdot 3 ^{- \frac{1}{2} + 1}}{10}

Subtract the numbers:

1 - \frac{1}{2} = \frac{1}{2}

= \frac{31 \cdot 3 ^{\frac{1}{2}}}{10}

Apply radical rule:

3^{\frac{1}{2}} = 3

= \frac{31 3}{10}

= \frac{3 \cdot 31}{10}

= \frac{31 3}{10}

sin (15 5^{\circ})

arctan (0.65)

arctan (0.72)

sin^{2} (7 5^{\circ})

arctan (- 15)

What is the value of (9.3)/(tan(60)) ?
The value of (9.3)/(tan(60)) is (31sqrt(3))/(10)