What is the value of tan(60)-sin(60)-tan(60) ?

The value of tan(60)-sin(60)-tan(60) is -(sqrt(3))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tan(60)-sin(60)-tan(60)

tan (6 0^{\circ}) - sin (6 0^{\circ}) - tan (6 0^{\circ})

- \frac{3}{2}

Decimal Notation

- 0.86602 \dots

Solution steps

tan (6 0^{\circ}) - sin (6 0^{\circ}) - tan (6 0^{\circ})

Use the following trivial identity:

tan (6 0^{\circ}) = 3

tan (6 0^{\circ})

tan (x)

periodicity table with

18 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

= 3

Use the following trivial identity:

sin (6 0^{\circ}) = \frac{3}{2}

sin (6 0^{\circ})

sin (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{3}{2}

= 3 - \frac{3}{2} - 3

Simplify

= - \frac{3}{2}

tan (5 0^{\circ}) \cdot 1.3

15.24 tan (4 1^{\circ})

sin (12 0^{\circ}) + cos (21 0^{\circ}) - tan (22 5^{\circ})

- 1 sin (\frac{π}{2})

1 cos (2 5^{\circ})

What is the value of tan(60)-sin(60)-tan(60) ?
The value of tan(60)-sin(60)-tan(60) is -(sqrt(3))/2