What is the value of (sin(30)+cot(60))(tan(60)) ?

The value of (sin(30)+cot(60))(tan(60)) is (1/2+(sqrt(3))/3)sqrt(3)

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(sin(30)+cot(60))(tan(60))

(sin (3 0^{\circ}) + cot (6 0^{\circ})) (tan (6 0^{\circ}))

(\frac{1}{2} + \frac{3}{3}) 3

Decimal Notation

1.86602 \dots

Solution steps

(sin (3 0^{\circ}) + cot (6 0^{\circ})) (tan (6 0^{\circ}))

= (sin (3 0^{\circ}) + cot (6 0^{\circ})) tan (6 0^{\circ})

Use the following trivial identity:

sin (3 0^{\circ}) = \frac{1}{2}

sin (3 0^{\circ})

sin (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{1}{2}

Use the following trivial identity:

cot (6 0^{\circ}) = \frac{3}{3}

cot (6 0^{\circ})

cot (x)

periodicity table with

18 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cot (x) \mp \infty 31 \frac{3}{3} 0 - \frac{3}{3} - 1 - 3

= \frac{3}{3}

Use the following trivial identity:

tan (6 0^{\circ}) = 3

tan (6 0^{\circ})

tan (x)

periodicity table with

18 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

= 3

= (\frac{1}{2} + \frac{3}{3}) 3

\frac{6 sin ( 7 0 ^{\circ} )}{sin ( 4 2 ^{\circ} )}

sin (3 0^{\circ}) cos (6 0^{\circ}) - sin (6 0^{\circ}) cos (3 0^{\circ})

cos (2 π - \frac{π}{4})

arcsin (0.9779)

3 sin (3 8^{\circ})

What is the value of (sin(30)+cot(60))(tan(60)) ?
The value of (sin(30)+cot(60))(tan(60)) is (1/2+(sqrt(3))/3)sqrt(3)