What is the value of 1/(sec^2(0+0))-1 ?

The value of 1/(sec^2(0+0))-1 is 0

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1/(sec^2(0+0))-1

\frac{1}{sec ^{2} ( 0 + 0 )} - 1

0

Solution steps

\frac{1}{sec ^{2} ( 0 + 0 )} - 1

Simplify:

0 + 0 = 0

0 + 0

Add the numbers:

0 + 0 = 0

= 0

\frac{1}{sec ^{2} ( 0 )} - 1 = \frac{1 - sec ^{2} ( 0 )}{sec ^{2} ( 0 )}

\frac{1}{sec ^{2} ( 0 )} - 1

Convert element to fraction:

1 = \frac{1 sec ^{2} ( 0 )}{sec ^{2} ( 0 )}

= \frac{1}{sec ^{2} ( 0 )} - \frac{1 \cdot sec ^{2} ( 0 )}{sec ^{2} ( 0 )}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 - 1 \cdot sec ^{2} ( 0 )}{sec ^{2} ( 0 )}

Multiply:

1 \cdot sec^{2} (0) = sec^{2} (0)

= \frac{1 - sec ^{2} ( 0 )}{sec ^{2} ( 0 )}

= \frac{1 - sec ^{2} ( 0 )}{sec ^{2} ( 0 )}

Use the following trivial identity:

sec (0) = 1

sec (0)

sec (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

= 1

= \frac{1 - 1 ^{2}}{1 ^{2}}

Simplify

= 0

arccos (\frac{70}{100}) \cdot 2

arctan (2.031)

sin (arccos (\frac{3}{8}))

- 3 sin (\frac{4 π}{3})

sin^{2} (3 7^{\circ}) + cos^{2} (3 7^{\circ})