What is the value of csc(-(17pi)/6) ?

The value of csc(-(17pi)/6) is -2

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csc(-(17pi)/6)

csc (- \frac{17 π}{6})

- 2

Solution steps

csc (- \frac{17 π}{6})

Use the following property:

csc (- x) = - csc (x)

csc (- \frac{17 π}{6}) = - csc (\frac{17 π}{6})

= - csc (\frac{17 π}{6})

csc (\frac{17 π}{6}) = csc (\frac{5 π}{6})

csc (\frac{17 π}{6})

Rewrite

\frac{17 π}{6}

2 π + \frac{5 π}{6}

= csc (2 π + \frac{5 π}{6})

Apply the periodicity of

csc

csc (x + 2 π) = csc (x)

csc (2 π + \frac{5 π}{6}) = csc (\frac{5 π}{6})

= csc (\frac{5 π}{6})

= - csc (\frac{5 π}{6})

Rewrite using trig identities:

csc (\frac{5 π}{6}) = 2

csc (\frac{5 π}{6})

Rewrite using trig identities:

\frac{1}{sin ( \frac{5 π}{6} )}

csc (\frac{5 π}{6})

Use the basic trigonometric identity:

csc (x) = \frac{1}{sin ( x )}

= \frac{1}{sin ( \frac{5 π}{6} )}

= \frac{1}{sin ( \frac{5 π}{6} )}

Use the following trivial identity:

sin (\frac{5 π}{6}) = \frac{1}{2}

sin (\frac{5 π}{6})

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{1}{2}

= \frac{1}{\frac{1}{2}}

Simplify

= 2

= - 2

arctan (2.75)

tan (\frac{38.71}{8.22})

arccsc (csc (- \frac{π}{4}))

arctan (\frac{- 3}{- 6})

sinh (- 5)