What is the value of 38cos(60) ?

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38cos(60)

38 cos (6 0^{\circ})

19

Solution steps

38 cos (6 0^{\circ})

Use the following trivial identity:

cos (6 0^{\circ}) = \frac{1}{2}

cos (6 0^{\circ})

cos (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= \frac{1}{2}

= 38 \cdot \frac{1}{2}

Simplify

38 \cdot \frac{1}{2} : 19

38 \cdot \frac{1}{2}

Convert element to fraction:

38 = \frac{38}{1}

= \frac{1}{2} \cdot \frac{38}{1}

Cross-cancel common factor:

2

= \frac{19}{1}

Apply the fraction rule:

\frac{a}{1} = a

= 19

= 19

- 50 \cdot 9.81 \cdot sin (3 7^{\circ}) \cdot 3

2 (- 2.19) cos (2 (- 2.19)) - ((- 2.19) + 1)^{2}

sin (\frac{5}{3}) π

1 + 2 cos (\frac{4 π}{3})

- \frac{2 cot ( \frac{π}{6} ) csc ( \frac{π}{6} )}{( 1 - csc ( \frac{π}{6} ) ) ^{2}}