What is the value of tan(3330+90)+tan(3870-90) ?

The value of tan(3330+90)+tan(3870-90) is 0

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tan(3330+90)+tan(3870-90)

tan (333 0^{\circ} + 9 0^{\circ}) + tan (387 0^{\circ} - 9 0^{\circ})

0

Solution steps

tan (333 0^{\circ} + 9 0^{\circ}) + tan (387 0^{\circ} - 9 0^{\circ})

Simplify

= tan (342 0^{\circ}) + tan (378 0^{\circ})

tan (342 0^{\circ}) = tan (0)

tan (342 0^{\circ})

Rewrite

342 0^{\circ}

18 0^{\circ} \cdot 19 + 0

= tan (18 0^{\circ} 19 + 0)

Apply the periodicity of

tan

tan (x + 18 0^{\circ} \cdot k) = tan (x)

tan (18 0^{\circ} \cdot 19 + 0) = tan (0)

= tan (0)

= tan (0) + tan (378 0^{\circ})

tan (378 0^{\circ}) = tan (0)

tan (378 0^{\circ})

Rewrite

378 0^{\circ}

18 0^{\circ} \cdot 21 + 0

= tan (18 0^{\circ} 21 + 0)

Apply the periodicity of

tan

tan (x + 18 0^{\circ} \cdot k) = tan (x)

tan (18 0^{\circ} \cdot 21 + 0) = tan (0)

= tan (0)

= tan (0) + tan (0)

Simplify

= 2 tan (0)

Use the following trivial identity:

tan (0) = 0

tan (0)

tan (x)

periodicity table with

18 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

= 0

= 2 \cdot 0

Simplify

= 0

arctan (\frac{1}{- 6})

cos (1.05)

arcsin (- 0.58)

1.004 \cdot cos (0.001)

sin (- (\frac{π}{2}))

What is the value of tan(3330+90)+tan(3870-90) ?
The value of tan(3330+90)+tan(3870-90) is 0