What is the value of sin(arccos(1/5)) ?

The value of sin(arccos(1/5)) is (2sqrt(6))/5

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sin(arccos(1/5))

sin (arccos (\frac{1}{5}))

\frac{2 6}{5}

Decimal Notation

0.97979 \dots

Solution steps

sin (arccos (\frac{1}{5}))

Rewrite using trig identities:

sin (arccos (\frac{1}{5})) = 1 - (\frac{1}{5})^{2}

Use the following identity:

sin (arccos (x)) = 1 - x^{2}

= 1 - (\frac{1}{5})^{2}

= 1 - (\frac{1}{5})^{2}

Simplify

= \frac{2 6}{5}

\frac{sin ( 4 5 ^{\circ} )}{1.41}

tanh (ln (3)) - tanh (0)

cos^{2} (0.6)

cos (4 0^{\circ}) \cdot 8

13 cos (5 4^{\circ})

What is the value of sin(arccos(1/5)) ?
The value of sin(arccos(1/5)) is (2sqrt(6))/5