What is the general solution for cot(x)=1,0<= x<= 2pi ?

The general solution for cot(x)=1,0<= x<= 2pi is x= pi/4 ,x=(5pi)/4

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cot(x)=1,0<= x<= 2pi

cot (x) = 1, 0 \leq x \leq 2 π

x = \frac{π}{4}, x = \frac{5 π}{4}

Degrees

x = 4 5^{\circ}, x = 22 5^{\circ}

Solution steps

cot (x) = 1, 0 \leq x \leq 2 π

General solutions for

cot (x) = 1

cot (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cot (x) \mp \infty 31 \frac{3}{3} 0 - \frac{3}{3} - 1 - 3

x = \frac{π}{4} + πn

x = \frac{π}{4} + πn

Solutions for the range

0 \leq x \leq 2 π

x = \frac{π}{4}, x = \frac{5 π}{4}

sin^{2} (x) = \frac{1}{4}

tan (- \frac{π}{4})

3 tan (θ) + 1 = 0

sin (x) cos (y) = \frac{1}{2} (sin (x + y) + sin (x - y))

tan (\frac{7 π}{4})

What is the general solution for cot(x)=1,0<= x<= 2pi ?
The general solution for cot(x)=1,0<= x<= 2pi is x= pi/4 ,x=(5pi)/4