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受欢迎的三角函数 >

3tan(2x)+sqrt(3)=0

解答

3 tan (2 x) + 3 = 0

解答

x = \frac{5 π}{12} + \frac{πn}{2}

+1

度数

x = 7 5^{\circ} + 9 0^{\circ} n

求解步骤

3 tan (2 x) + 3 = 0

将

3

到右边

3 tan (2 x) + 3 = 0

两边减去

3

3 tan (2 x) + 3 - 3 = 0 - 3

化简

3 tan (2 x) = - 3

3 tan (2 x) = - 3

两边除以

3

3 tan (2 x) = - 3

两边除以

3

\frac{3 tan ( 2 x )}{3} = \frac{- 3}{3}

化简

tan (2 x) = - \frac{3}{3}

tan (2 x) = - \frac{3}{3}

tan (2 x) = - \frac{3}{3}

的通解

tan (x)

周期表（周期为

πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

2 x = \frac{5 π}{6} + πn

2 x = \frac{5 π}{6} + πn

解

2 x = \frac{5 π}{6} + πn : x = \frac{5 π}{12} + \frac{πn}{2}

2 x = \frac{5 π}{6} + πn

两边除以

2

2 x = \frac{5 π}{6} + πn

两边除以

2

\frac{2 x}{2} = \frac{\frac{5 π}{6}}{2} + \frac{πn}{2}

化简

\frac{2 x}{2} = \frac{\frac{5 π}{6}}{2} + \frac{πn}{2}

化简

\frac{2 x}{2} : x

\frac{2 x}{2}

数字相除:

\frac{2}{2} = 1

= x

化简

\frac{\frac{5 π}{6}}{2} + \frac{πn}{2} : \frac{5 π}{12} + \frac{πn}{2}

\frac{\frac{5 π}{6}}{2} + \frac{πn}{2}

\frac{\frac{5 π}{6}}{2} = \frac{5 π}{12}

\frac{\frac{5 π}{6}}{2}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{5 π}{6 \cdot 2}

数字相乘:

6 \cdot 2 = 12

= \frac{5 π}{12}

= \frac{5 π}{12} + \frac{πn}{2}

x = \frac{5 π}{12} + \frac{πn}{2}

x = \frac{5 π}{12} + \frac{πn}{2}

x = \frac{5 π}{12} + \frac{πn}{2}

x = \frac{5 π}{12} + \frac{πn}{2}

作图

流行的例子

tan(2x+13)=cot(x+53)

tan (2 x + 13) = cot (x + 5 3^{\circ})

sin(2x)-sqrt(3)sin(x)=0

sin (2 x) - 3 sin (x) = 0

2sin(2x)+sqrt(3)cos(x)=0

2 sin (2 x) + 3 cos (x) = 0

-6sqrt(3)cot(θ)+1=-5

- 63 cot (θ) + 1 = - 5

5 - 10 sin (2 x) = 0