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受欢迎的三角函数 >

sin(x^2+3x+5)=0

解答

sin (x^{2} + 3 x + 5) = 0

解答

x = \frac{- 3 + 8 πn - 11}{2}, x = \frac{- 3 - 8 πn - 11}{2}, x = \frac{- 3 + 8 πn + 4 π - 11}{2}, x = \frac{- 3 - 8 πn + 4 π - 11}{2}

+1

度数

x = - 85.94366 \dots^{\circ} + 107.69755 \dots^{\circ} n, x = - 85.94366 \dots^{\circ} - 107.69755 \dots^{\circ} n, x = - 85.94366 \dots^{\circ} + 148.02703 \dots^{\circ} n, x = - 85.94366 \dots^{\circ} - 148.02703 \dots^{\circ} n

求解步骤

sin (x^{2} + 3 x + 5) = 0

sin (x^{2} + 3 x + 5) = 0

的通解

sin (x)

周期表（周期为

2 πn

"）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x^{2} + 3 x + 5 = 0 + 2 πn, x^{2} + 3 x + 5 = π + 2 πn

x^{2} + 3 x + 5 = 0 + 2 πn, x^{2} + 3 x + 5 = π + 2 πn

解

x^{2} + 3 x + 5 = 0 + 2 πn : x = \frac{- 3 + 8 πn - 11}{2}, x = \frac{- 3 - 8 πn - 11}{2}

x^{2} + 3 x + 5 = 0 + 2 πn

展开

0 + 2 πn : 2 πn

0 + 2 πn

0 + 2 πn = 2 πn

= 2 πn

x^{2} + 3 x + 5 = 2 πn

将

2 πn

para o lado esquerdo

x^{2} + 3 x + 5 = 2 πn

两边减去

2 πn

x^{2} + 3 x + 5 - 2 πn = 2 πn - 2 πn

化简

x^{2} + 3 x + 5 - 2 πn = 0

x^{2} + 3 x + 5 - 2 πn = 0

使用求根公式求解

x^{2} + 3 x + 5 - 2 πn = 0

二次方程求根公式:

若

a = 1, b = 3, c = 5 - 2 πn

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( 5 - 2 πn )}{2 \cdot 1}

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( 5 - 2 πn )}{2 \cdot 1}

化简

3^{2} - 4 \cdot 1 \cdot (5 - 2 πn) : 8 πn - 11

3^{2} - 4 \cdot 1 \cdot (5 - 2 πn)

数字相乘:

4 \cdot 1 = 4

= 3^{2} - 4 (- 2 πn + 5)

3^{2} = 9

= 9 - 4 (- 2 πn + 5)

乘开

9 - 4 (5 - 2 πn) : 8 πn - 11

9 - 4 (5 - 2 πn)

乘开

- 4 (5 - 2 πn) : - 20 + 8 πn

- 4 (5 - 2 πn)

使用分配律:

a (b - c) = ab - a c

a = - 4, b = 5, c = 2 πn

= - 4 \cdot 5 - (- 4) \cdot 2 πn

使用加减运算法则

- (- a) = a

= - 4 \cdot 5 + 4 \cdot 2 πn

化简

- 4 \cdot 5 + 4 \cdot 2 πn : - 20 + 8 πn

- 4 \cdot 5 + 4 \cdot 2 πn

数字相乘:

4 \cdot 5 = 20

= - 20 + 4 \cdot 2 πn

数字相乘:

4 \cdot 2 = 8

= - 20 + 8 πn

= - 20 + 8 πn

= 9 - 20 + 8 πn

数字相减:

9 - 20 = - 11

= 8 πn - 11

= 8 πn - 11

x_{1, 2} = \frac{- 3 \pm 8 πn - 11}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- 3 + 8 πn - 11}{2 \cdot 1}, x_{2} = \frac{- 3 - 8 πn - 11}{2 \cdot 1}

x = \frac{- 3 + 8 πn - 11}{2 \cdot 1} : \frac{- 3 + 8 πn - 11}{2}

\frac{- 3 + 8 πn - 11}{2 \cdot 1}

数字相乘:

2 \cdot 1 = 2

= \frac{- 3 + 8 πn - 11}{2}

x = \frac{- 3 - 8 πn - 11}{2 \cdot 1} : \frac{- 3 - 8 πn - 11}{2}

\frac{- 3 - 8 πn - 11}{2 \cdot 1}

数字相乘:

2 \cdot 1 = 2

= \frac{- 3 - 8 πn - 11}{2}

二次方程组的解是:

x = \frac{- 3 + 8 πn - 11}{2}, x = \frac{- 3 - 8 πn - 11}{2}

解

x^{2} + 3 x + 5 = π + 2 πn : x = \frac{- 3 + 8 πn + 4 π - 11}{2}, x = \frac{- 3 - 8 πn + 4 π - 11}{2}

x^{2} + 3 x + 5 = π + 2 πn

将

2 πn

para o lado esquerdo

x^{2} + 3 x + 5 = π + 2 πn

两边减去

2 πn

x^{2} + 3 x + 5 - 2 πn = π + 2 πn - 2 πn

化简

x^{2} + 3 x + 5 - 2 πn = π

x^{2} + 3 x + 5 - 2 πn = π

将

π

para o lado esquerdo

x^{2} + 3 x + 5 - 2 πn = π

两边减去

π

x^{2} + 3 x + 5 - 2 πn - π = π - π

化简

x^{2} + 3 x + 5 - 2 πn - π = 0

x^{2} + 3 x + 5 - 2 πn - π = 0

使用求根公式求解

x^{2} + 3 x + 5 - 2 πn - π = 0

二次方程求根公式:

若

a = 1, b = 3, c = 5 - 2 πn - π

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( 5 - 2 πn - π )}{2 \cdot 1}

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( 5 - 2 πn - π )}{2 \cdot 1}

化简

3^{2} - 4 \cdot 1 \cdot (5 - 2 πn - π) : 8 πn + 4 π - 11

3^{2} - 4 \cdot 1 \cdot (5 - 2 πn - π)

数字相乘:

4 \cdot 1 = 4

= 3^{2} - 4 (- 2 πn - π + 5)

3^{2} = 9

= 9 - 4 (- 2 πn - π + 5)

乘开

9 - 4 (5 - 2 πn - π) : 8 πn + 4 π - 11

9 - 4 (5 - 2 πn - π)

乘开

- 4 (5 - 2 πn - π) : - 20 + 8 πn + 4 π

- 4 (5 - 2 πn - π)

打开括号

= (- 4) \cdot 5 + (- 4) (- 2 πn) + (- 4) (- π)

使用加减运算法则

+ (- a) = - a, (- a) (- b) = ab

= - 4 \cdot 5 + 4 \cdot 2 πn + 4 π

化简

- 4 \cdot 5 + 4 \cdot 2 πn + 4 π : - 20 + 8 πn + 4 π

- 4 \cdot 5 + 4 \cdot 2 πn + 4 π

数字相乘:

4 \cdot 5 = 20

= - 20 + 4 \cdot 2 πn + 4 π

数字相乘:

4 \cdot 2 = 8

= - 20 + 8 πn + 4 π

= - 20 + 8 πn + 4 π

= 9 - 20 + 8 πn + 4 π

数字相减:

9 - 20 = - 11

= 8 πn + 4 π - 11

= 8 πn + 4 π - 11

x_{1, 2} = \frac{- 3 \pm 8 πn + 4 π - 11}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- 3 + 8 πn + 4 π - 11}{2 \cdot 1}, x_{2} = \frac{- 3 - 8 πn + 4 π - 11}{2 \cdot 1}

x = \frac{- 3 + 8 πn + 4 π - 11}{2 \cdot 1} : \frac{- 3 + 8 πn + 4 π - 11}{2}

\frac{- 3 + 8 πn + 4 π - 11}{2 \cdot 1}

数字相乘:

2 \cdot 1 = 2

= \frac{- 3 + 8 πn + 4 π - 11}{2}

x = \frac{- 3 - 8 πn + 4 π - 11}{2 \cdot 1} : \frac{- 3 - 8 πn + 4 π - 11}{2}

\frac{- 3 - 8 πn + 4 π - 11}{2 \cdot 1}

数字相乘:

2 \cdot 1 = 2

= \frac{- 3 - 8 πn + 4 π - 11}{2}

二次方程组的解是:

x = \frac{- 3 + 8 πn + 4 π - 11}{2}, x = \frac{- 3 - 8 πn + 4 π - 11}{2}

x = \frac{- 3 + 8 πn - 11}{2}, x = \frac{- 3 - 8 πn - 11}{2}, x = \frac{- 3 + 8 πn + 4 π - 11}{2}, x = \frac{- 3 - 8 πn + 4 π - 11}{2}

作图

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