What is the general solution for 5cos(t)=0 ?

The general solution for 5cos(t)=0 is t= pi/2+2pin,t=(3pi)/2+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5cos(t)=0

5 cos (t) = 0

t = \frac{π}{2} + 2 πn, t = \frac{3 π}{2} + 2 πn

Degrees

t = 9 0^{\circ} + 36 0^{\circ} n, t = 27 0^{\circ} + 36 0^{\circ} n

Solution steps

5 cos (t) = 0

Divide both sides by

5

5 cos (t) = 0

Divide both sides by

5

\frac{5 cos ( t )}{5} = \frac{0}{5}

Simplify

cos (t) = 0

cos (t) = 0

General solutions for

cos (t) = 0

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

t = \frac{π}{2} + 2 πn, t = \frac{3 π}{2} + 2 πn

t = \frac{π}{2} + 2 πn, t = \frac{3 π}{2} + 2 πn

2 cos (\frac{x}{2}) = 1

cos (x) = \frac{6}{10}

sec^{2} (x) - 2 tan^{2} (x) = \frac{2}{3}

cos^{2} (x) - 3 cos (x) - 1 = 0

cos (3 x) = - sin (x + \frac{π}{6})

What is the general solution for 5cos(t)=0 ?
The general solution for 5cos(t)=0 is t= pi/2+2pin,t=(3pi)/2+2pin