What is the general solution for 10cos(θ)=6 ?

The general solution for 10cos(θ)=6 is θ=0.92729…+2pin,θ=2pi-0.92729…+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

10cos(θ)=6

10 cos (θ) = 6

θ = 0.92729 \dots + 2 πn, θ = 2 π - 0.92729 \dots + 2 πn

Degrees

θ = 53.13010 \dots^{\circ} + 36 0^{\circ} n, θ = 306.86989 \dots^{\circ} + 36 0^{\circ} n

Solution steps

10 cos (θ) = 6

Divide both sides by

10

10 cos (θ) = 6

Divide both sides by

10

\frac{10 cos ( θ )}{10} = \frac{6}{10}

Simplify

cos (θ) = \frac{3}{5}

cos (θ) = \frac{3}{5}

Apply trig inverse properties

cos (θ) = \frac{3}{5}

General solutions for

cos (θ) = \frac{3}{5}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{3}{5}) + 2 πn, θ = 2 π - arccos (\frac{3}{5}) + 2 πn

θ = arccos (\frac{3}{5}) + 2 πn, θ = 2 π - arccos (\frac{3}{5}) + 2 πn

Show solutions in decimal form

θ = 0.92729 \dots + 2 πn, θ = 2 π - 0.92729 \dots + 2 πn

- cos (x) = cos (- x)

5 sin (θ) + 1 = 3 sin (θ)

sin (x) = 1 + cos (x)

- 2 sin^{2} (x) = sin (x)

sin (2 x) = 0.8

What is the general solution for 10cos(θ)=6 ?
The general solution for 10cos(θ)=6 is θ=0.92729…+2pin,θ=2pi-0.92729…+2pin