What is the general solution for cos(θ)= 8/9 ?

The general solution for cos(θ)= 8/9 is θ=0.47588…+2pin,θ=2pi-0.47588…+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cos(θ)= 8/9

cos (θ) = \frac{8}{9}

θ = 0.47588 \dots + 2 πn, θ = 2 π - 0.47588 \dots + 2 πn

Degrees

θ = 27.26604 \dots^{\circ} + 36 0^{\circ} n, θ = 332.73395 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (θ) = \frac{8}{9}

Apply trig inverse properties

cos (θ) = \frac{8}{9}

General solutions for

cos (θ) = \frac{8}{9}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{8}{9}) + 2 πn, θ = 2 π - arccos (\frac{8}{9}) + 2 πn

θ = arccos (\frac{8}{9}) + 2 πn, θ = 2 π - arccos (\frac{8}{9}) + 2 πn

Show solutions in decimal form

θ = 0.47588 \dots + 2 πn, θ = 2 π - 0.47588 \dots + 2 πn

2 sin (x) - cos (x) = 0, 0^{\circ} \leq x \leq 36 0^{\circ}

8 tan (A) + 3 = 2 tan (A) + 3

cosh (x) = 3

2 sec (x) + 1 = 0

cot (x) = - 3

What is the general solution for cos(θ)= 8/9 ?
The general solution for cos(θ)= 8/9 is θ=0.47588…+2pin,θ=2pi-0.47588…+2pin