What is the general solution for tan(θ)=(-1)/1 ?

The general solution for tan(θ)=(-1)/1 is θ=(3pi)/4+pin

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tan(θ)=(-1)/1

tan (θ) = \frac{- 1}{1}

θ = \frac{3 π}{4} + πn

Degrees

θ = 13 5^{\circ} + 18 0^{\circ} n

Solution steps

tan (θ) = \frac{- 1}{1}

Apply rule

\frac{a}{1} = a

tan (θ) = - 1

General solutions for

tan (θ) = - 1

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

θ = \frac{3 π}{4} + πn

θ = \frac{3 π}{4} + πn

cot (x) = 3

cos (\frac{θ}{2}) = - 1

2 sin (x) + \frac{3}{4} = \frac{3}{2} sin (x)

- 2 cos^{2} (θ) + sin (θ) + 5 = 4

12 sin^{2} (x) - 9 = 0

What is the general solution for tan(θ)=(-1)/1 ?
The general solution for tan(θ)=(-1)/1 is θ=(3pi)/4+pin