What is the general solution for cot(x)=1,0<= x<2pi ?

The general solution for cot(x)=1,0<= x<2pi is x= pi/4 ,x=(5pi)/4

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cot(x)=1,0<= x<2pi

cot (x) = 1, 0 \leq x < 2 π

x = \frac{π}{4}, x = \frac{5 π}{4}

Degrees

x = 4 5^{\circ}, x = 22 5^{\circ}

Solution steps

cot (x) = 1, 0 \leq x < 2 π

General solutions for

cot (x) = 1

cot (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cot (x) \mp \infty 31 \frac{3}{3} 0 - \frac{3}{3} - 1 - 3

x = \frac{π}{4} + πn

x = \frac{π}{4} + πn

Solutions for the range

0 \leq x < 2 π

x = \frac{π}{4}, x = \frac{5 π}{4}

sin (4 x) cos (6 x) - cos (4 x) sin (6 x) = - 0.75

cos (2 x) = 0.685

4 tan^{2} (x) = 12

cos (θ) = - 0.71

cos (θ) = \frac{60}{61}

What is the general solution for cot(x)=1,0<= x<2pi ?
The general solution for cot(x)=1,0<= x<2pi is x= pi/4 ,x=(5pi)/4