sec(θ)= 6/5

解

sec (θ) = \frac{6}{5}

θ = 0.58568 \dots + 2 πn, θ = 2 π - 0.58568 \dots + 2 πn

度

θ = 33.55730 \dots^{\circ} + 36 0^{\circ} n, θ = 326.44269 \dots^{\circ} + 36 0^{\circ} n

解答ステップ

sec (θ) = \frac{6}{5}

三角関数の逆数プロパティを適用する

sec (θ) = \frac{6}{5}

以下の一般解

sec (θ) = \frac{6}{5}

sec (x) = a \Rightarrow x = arcsec (a) + 2 πn, x = 2 π - arcsec (a) + 2 πn

θ = arcsec (\frac{6}{5}) + 2 πn, θ = 2 π - arcsec (\frac{6}{5}) + 2 πn

θ = arcsec (\frac{6}{5}) + 2 πn, θ = 2 π - arcsec (\frac{6}{5}) + 2 πn

10進法形式で解を証明する

θ = 0.58568 \dots + 2 πn, θ = 2 π - 0.58568 \dots + 2 πn