What is the general solution for solvefor x,cos(x)=-1/2 ?

The general solution for solvefor x,cos(x)=-1/2 is x=(2pi)/3+2pin,x=(4pi)/3+2pin

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solvefor x,cos(x)=-1/2

solve for

x, cos (x) = - \frac{1}{2}

x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

Degrees

x = 12 0^{\circ} + 36 0^{\circ} n, x = 24 0^{\circ} + 36 0^{\circ} n

Solution steps

cos (x) = - \frac{1}{2}

General solutions for

cos (x) = - \frac{1}{2}

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

x, θ = arctan (\frac{y}{x})

cos (x) tan (x) = 10 tan (x)

cos (2 x) = \frac{3}{5}

- 4 cos (2 x) = 0

x, arcsin (y) = arcsin (x) + \frac{π}{3}

What is the general solution for solvefor x,cos(x)=-1/2 ?
The general solution for solvefor x,cos(x)=-1/2 is x=(2pi)/3+2pin,x=(4pi)/3+2pin