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受欢迎的三角函数 >

4csc(θ)+5=0

解答

4 csc (θ) + 5 = 0

解答

θ = - 0.92729 \dots + 2 πn, θ = π + 0.92729 \dots + 2 πn

+1

度数

θ = - 53.13010 \dots^{\circ} + 36 0^{\circ} n, θ = 233.13010 \dots^{\circ} + 36 0^{\circ} n

求解步骤

4 csc (θ) + 5 = 0

将

5

到右边

4 csc (θ) + 5 = 0

两边减去

5

4 csc (θ) + 5 - 5 = 0 - 5

化简

4 csc (θ) = - 5

4 csc (θ) = - 5

两边除以

4

4 csc (θ) = - 5

两边除以

4

\frac{4 csc ( θ )}{4} = \frac{- 5}{4}

化简

csc (θ) = - \frac{5}{4}

csc (θ) = - \frac{5}{4}

使用反三角函数性质

csc (θ) = - \frac{5}{4}

csc (θ) = - \frac{5}{4}

的通解

csc (x) = - a \Rightarrow x = arccsc (- a) + 2 πn, x = π + arccsc (a) + 2 πn

θ = arccsc (- \frac{5}{4}) + 2 πn, θ = π + arccsc (\frac{5}{4}) + 2 πn

θ = arccsc (- \frac{5}{4}) + 2 πn, θ = π + arccsc (\frac{5}{4}) + 2 πn

以小数形式表示解

θ = - 0.92729 \dots + 2 πn, θ = π + 0.92729 \dots + 2 πn

作图

流行的例子

cos(x)=-cos(x)+2

cos (x) = - cos (x) + 2

4 cos^{2} (2 x) - 3 = 0

2sin(x)cos(x)-sqrt(3)sin(x)=0

2 sin (x) cos (x) - 3 sin (x) = 0

10cos^2(x)+13cos(x)+4=0

10 cos^{2} (x) + 13 cos (x) + 4 = 0

4 cos^{2} (2 x) - 1 = 1