sec(t)=2

Lösung

sec (t) = 2

t = \frac{π}{3} + 2 πn, t = \frac{5 π}{3} + 2 πn

Grad

t = 6 0^{\circ} + 36 0^{\circ} n, t = 30 0^{\circ} + 36 0^{\circ} n

Schritte zur Lösung

sec (t) = 2

Allgemeine Lösung für

sec (t) = 2

sec (x)

Periodizitätstabelle mit

2 πn

Zyklus:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

t = \frac{π}{3} + 2 πn, t = \frac{5 π}{3} + 2 πn

t = \frac{π}{3} + 2 πn, t = \frac{5 π}{3} + 2 πn

2 cos^{2} (x) = - cos (x)

2 tan^{2} (x) + 5 tan (x) + 3 = 0

csc^{2} (x) = 4

3 tanh (2 θ) = 5 sech (θ) + 1

2 cos^{2} (θ) + cos (θ) = 1