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受欢迎的三角函数 >

sin(2x)sin(x)+cos(x)=0

解答

sin (2 x) sin (x) + cos (x) = 0

解答

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

+1

度数

x = 9 0^{\circ} + 36 0^{\circ} n, x = 27 0^{\circ} + 36 0^{\circ} n

求解步骤

sin (2 x) sin (x) + cos (x) = 0

使用三角恒等式改写

cos (x) + sin (2 x) sin (x)

使用倍角公式:

sin (2 x) = 2 sin (x) cos (x)

= cos (x) + 2 sin (x) cos (x) sin (x)

2 sin (x) cos (x) sin (x) = 2 sin^{2} (x) cos (x)

2 sin (x) cos (x) sin (x)

使用指数法则:

a^{b} \cdot a^{c} = a^{b + c}

sin (x) sin (x) = sin^{1 + 1} (x)

= 2 cos (x) sin^{1 + 1} (x)

数字相加:

1 + 1 = 2

= 2 cos (x) sin^{2} (x)

= cos (x) + 2 sin^{2} (x) cos (x)

cos (x) + 2 cos (x) sin^{2} (x) = 0

分解

cos (x) + 2 cos (x) sin^{2} (x) : cos (x) (2 sin^{2} (x) + 1)

cos (x) + 2 cos (x) sin^{2} (x)

因式分解出通项

cos (x)

= cos (x) (1 + 2 sin^{2} (x))

cos (x) (2 sin^{2} (x) + 1) = 0

分别求解每个部分

cos (x) = 0 or 2 sin^{2} (x) + 1 = 0

cos (x) = 0 : x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

cos (x) = 0

cos (x) = 0

的通解

cos (x)

周期表（周期为

2 πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

2 sin^{2} (x) + 1 = 0 :

无解

2 sin^{2} (x) + 1 = 0

用替代法求解

2 sin^{2} (x) + 1 = 0

令

: sin (x) = u

2 u^{2} + 1 = 0

2 u^{2} + 1 = 0 : u = i \frac{1}{2}, u = - i \frac{1}{2}

2 u^{2} + 1 = 0

将

1

到右边

2 u^{2} + 1 = 0

两边减去

1

2 u^{2} + 1 - 1 = 0 - 1

化简

2 u^{2} = - 1

2 u^{2} = - 1

两边除以

2

2 u^{2} = - 1

两边除以

2

\frac{2 u ^{2}}{2} = \frac{- 1}{2}

化简

u^{2} = - \frac{1}{2}

u^{2} = - \frac{1}{2}

对于

x^{2} = f (a)

解为

x = f (a), - f (a)

u = - \frac{1}{2}, u = - - \frac{1}{2}

化简

- \frac{1}{2} : i \frac{1}{2}

- \frac{1}{2}

使用根式运算法则:

- a = - 1 a

- \frac{1}{2} = - 1 \frac{1}{2}

= - 1 \frac{1}{2}

使用虚数运算法则:

- 1 = i

= i \frac{1}{2}

化简

- - \frac{1}{2} : - i \frac{1}{2}

- - \frac{1}{2}

化简

- \frac{1}{2} : i \frac{1}{2}

- \frac{1}{2}

使用根式运算法则:

- a = - 1 a

- \frac{1}{2} = - 1 \frac{1}{2}

= - 1 \frac{1}{2}

使用虚数运算法则:

- 1 = i

= i \frac{1}{2}

= - i \frac{1}{2}

u = i \frac{1}{2}, u = - i \frac{1}{2}

u = sin (x)

代回

sin (x) = i \frac{1}{2}, sin (x) = - i \frac{1}{2}

sin (x) = i \frac{1}{2}, sin (x) = - i \frac{1}{2}

sin (x) = i \frac{1}{2} :

无解

sin (x) = i \frac{1}{2}

无解

sin (x) = - i \frac{1}{2} :

无解

sin (x) = - i \frac{1}{2}

无解

合并所有解

无解

合并所有解

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

作图

流行的例子

sin(x)-2cos(x)=0

sin (x) - 2 cos (x) = 0

sec (x) = csc (x)

cos(x)=cos(x)sin(x)

cos (x) = cos (x) sin (x)

cos(2x)+sin(x)+2=0

cos (2 x) + sin (x) + 2 = 0

sqrt(3)tan(x)=-1

3 tan (x) = - 1