What is the general solution for sin(7x)=-(sqrt(3))/2 ?

The general solution for sin(7x)=-(sqrt(3))/2 is x=(4pi}{21}+(2pin)/7 ,x=(5pi)/(21)+\frac{2pin)/7

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Popular >

sin(7x)=-(sqrt(3))/2

Solution

sin (7 x) = - \frac{3}{2}

Solution

x = \frac{4 π}{21} + \frac{2 πn}{7}, x = \frac{5 π}{21} + \frac{2 πn}{7}

Degrees

x = 34.28571 \dots^{\circ} + 51.42857 \dots^{\circ} n, x = 42.85714 \dots^{\circ} + 51.42857 \dots^{\circ} n

Solution steps

sin (7 x) = - \frac{3}{2}

General solutions for

sin (7 x) = - \frac{3}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

7 x = \frac{4 π}{3} + 2 πn, 7 x = \frac{5 π}{3} + 2 πn

7 x = \frac{4 π}{3} + 2 πn, 7 x = \frac{5 π}{3} + 2 πn

Solve

7 x = \frac{4 π}{3} + 2 πn : x = \frac{4 π}{21} + \frac{2 πn}{7}

7 x = \frac{4 π}{3} + 2 πn

Divide both sides by

7

7 x = \frac{4 π}{3} + 2 πn

Divide both sides by

7

\frac{7 x}{7} = \frac{\frac{4 π}{3}}{7} + \frac{2 πn}{7}

Simplify

\frac{7 x}{7} = \frac{\frac{4 π}{3}}{7} + \frac{2 πn}{7}

Simplify

\frac{7 x}{7} : x

\frac{7 x}{7}

Divide the numbers:

\frac{7}{7} = 1

= x

Simplify

\frac{\frac{4 π}{3}}{7} + \frac{2 πn}{7} : \frac{4 π}{21} + \frac{2 πn}{7}

\frac{\frac{4 π}{3}}{7} + \frac{2 πn}{7}

\frac{\frac{4 π}{3}}{7} = \frac{4 π}{21}

\frac{\frac{4 π}{3}}{7}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{4 π}{3 \cdot 7}

Multiply the numbers:

3 \cdot 7 = 21

= \frac{4 π}{21}

= \frac{4 π}{21} + \frac{2 πn}{7}

x = \frac{4 π}{21} + \frac{2 πn}{7}

x = \frac{4 π}{21} + \frac{2 πn}{7}

x = \frac{4 π}{21} + \frac{2 πn}{7}

Solve

7 x = \frac{5 π}{3} + 2 πn : x = \frac{5 π}{21} + \frac{2 πn}{7}

7 x = \frac{5 π}{3} + 2 πn

Divide both sides by

7

7 x = \frac{5 π}{3} + 2 πn

Divide both sides by

7

\frac{7 x}{7} = \frac{\frac{5 π}{3}}{7} + \frac{2 πn}{7}

Simplify

\frac{7 x}{7} = \frac{\frac{5 π}{3}}{7} + \frac{2 πn}{7}

Simplify

\frac{7 x}{7} : x

\frac{7 x}{7}

Divide the numbers:

\frac{7}{7} = 1

= x

Simplify

\frac{\frac{5 π}{3}}{7} + \frac{2 πn}{7} : \frac{5 π}{21} + \frac{2 πn}{7}

\frac{\frac{5 π}{3}}{7} + \frac{2 πn}{7}

\frac{\frac{5 π}{3}}{7} = \frac{5 π}{21}

\frac{\frac{5 π}{3}}{7}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{5 π}{3 \cdot 7}

Multiply the numbers:

3 \cdot 7 = 21

= \frac{5 π}{21}

= \frac{5 π}{21} + \frac{2 πn}{7}

x = \frac{5 π}{21} + \frac{2 πn}{7}

x = \frac{5 π}{21} + \frac{2 πn}{7}

x = \frac{5 π}{21} + \frac{2 πn}{7}

x = \frac{4 π}{21} + \frac{2 πn}{7}, x = \frac{5 π}{21} + \frac{2 πn}{7}

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2 sin (θ) + 4 = 5

Frequently Asked Questions (FAQ)

What is the general solution for sin(7x)=-(sqrt(3))/2 ?
The general solution for sin(7x)=-(sqrt(3))/2 is x=(4pi}{21}+(2pin)/7 ,x=(5pi)/(21)+\frac{2pin)/7