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受欢迎的三角函数 >

sin(x+pi)-sin(x)+1=0

解答

sin (x + π) - sin (x) + 1 = 0

解答

x = 2 πn - \frac{π}{2} + \frac{2 π}{3}, x = 2 πn - \frac{π}{2} + \frac{4 π}{3}

+1

度数

x = 3 0^{\circ} + 36 0^{\circ} n, x = 15 0^{\circ} + 36 0^{\circ} n

求解步骤

sin (x + π) - sin (x) + 1 = 0

使用三角恒等式改写

sin (x + π) - sin (x) + 1

使用和差化积恒等式:

sin (s) - sin (t) = 2 sin (\frac{s - t}{2}) cos (\frac{s + t}{2})

= 1 + 2 sin (\frac{x + π - x}{2}) cos (\frac{x + π + x}{2})

2 sin (\frac{x + π - x}{2}) cos (\frac{x + π + x}{2}) = 2 cos (\frac{2 x + π}{2})

2 sin (\frac{x + π - x}{2}) cos (\frac{x + π + x}{2})

x + π - x = π

x + π - x

对同类项分组

= x - x + π

同类项相加:

x - x = 0

= π

= 2 sin (\frac{π}{2}) cos (\frac{x + x + π}{2})

x + π + x = 2 x + π

x + π + x

对同类项分组

= x + x + π

同类项相加:

x + x = 2 x

= 2 x + π

= 2 sin (\frac{π}{2}) cos (\frac{2 x + π}{2})

化简

sin (\frac{π}{2}) : 1

sin (\frac{π}{2})

使用以下普通恒等式:

sin (\frac{π}{2}) = 1

sin (x)

周期表（周期为

2 πn

"）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 1

= 2 \cdot 1 \cdot cos (\frac{2 x + π}{2})

数字相乘:

2 \cdot 1 = 2

= 2 cos (\frac{2 x + π}{2})

= 1 + 2 cos (\frac{2 x + π}{2})

1 + 2 cos (\frac{2 x + π}{2}) = 0

将

1

到右边

1 + 2 cos (\frac{2 x + π}{2}) = 0

两边减去

1

1 + 2 cos (\frac{2 x + π}{2}) - 1 = 0 - 1

化简

2 cos (\frac{2 x + π}{2}) = - 1

2 cos (\frac{2 x + π}{2}) = - 1

两边除以

2

2 cos (\frac{2 x + π}{2}) = - 1

两边除以

2

\frac{2 cos ( \frac{2 x + π}{2} )}{2} = \frac{- 1}{2}

化简

cos (\frac{2 x + π}{2}) = - \frac{1}{2}

cos (\frac{2 x + π}{2}) = - \frac{1}{2}

cos (\frac{2 x + π}{2}) = - \frac{1}{2}

的通解

cos (x)

周期表（周期为

2 πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

\frac{2 x + π}{2} = \frac{2 π}{3} + 2 πn, \frac{2 x + π}{2} = \frac{4 π}{3} + 2 πn

\frac{2 x + π}{2} = \frac{2 π}{3} + 2 πn, \frac{2 x + π}{2} = \frac{4 π}{3} + 2 πn

解

\frac{2 x + π}{2} = \frac{2 π}{3} + 2 πn : x = 2 πn - \frac{π}{2} + \frac{2 π}{3}

\frac{2 x + π}{2} = \frac{2 π}{3} + 2 πn

在两边乘以

2

\frac{2 x + π}{2} = \frac{2 π}{3} + 2 πn

在两边乘以

2

\frac{2 ( 2 x + π )}{2} = 2 \cdot \frac{2 π}{3} + 2 \cdot 2 πn

化简

\frac{2 ( 2 x + π )}{2} = 2 \cdot \frac{2 π}{3} + 2 \cdot 2 πn

化简

\frac{2 ( 2 x + π )}{2} : 2 x + π

\frac{2 ( 2 x + π )}{2}

数字相除:

\frac{2}{2} = 1

= 2 x + π

化简

2 \cdot \frac{2 π}{3} + 2 \cdot 2 πn : \frac{4 π}{3} + 4 πn

2 \cdot \frac{2 π}{3} + 2 \cdot 2 πn

2 \cdot \frac{2 π}{3} = \frac{4 π}{3}

2 \cdot \frac{2 π}{3}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 π 2}{3}

数字相乘:

2 \cdot 2 = 4

= \frac{4 π}{3}

2 \cdot 2 πn = 4 πn

2 \cdot 2 πn

数字相乘:

2 \cdot 2 = 4

= 4 πn

= \frac{4 π}{3} + 4 πn

2 x + π = \frac{4 π}{3} + 4 πn

2 x + π = \frac{4 π}{3} + 4 πn

2 x + π = \frac{4 π}{3} + 4 πn

将

π

到右边

2 x + π = \frac{4 π}{3} + 4 πn

两边减去

π

2 x + π - π = \frac{4 π}{3} + 4 πn - π

化简

2 x = \frac{4 π}{3} + 4 πn - π

2 x = \frac{4 π}{3} + 4 πn - π

两边除以

2

2 x = \frac{4 π}{3} + 4 πn - π

两边除以

2

\frac{2 x}{2} = \frac{\frac{4 π}{3}}{2} + \frac{4 πn}{2} - \frac{π}{2}

化简

\frac{2 x}{2} = \frac{\frac{4 π}{3}}{2} + \frac{4 πn}{2} - \frac{π}{2}

化简

\frac{2 x}{2} : x

\frac{2 x}{2}

数字相除:

\frac{2}{2} = 1

= x

化简

\frac{\frac{4 π}{3}}{2} + \frac{4 πn}{2} - \frac{π}{2} : 2 πn - \frac{π}{2} + \frac{2 π}{3}

\frac{\frac{4 π}{3}}{2} + \frac{4 πn}{2} - \frac{π}{2}

对同类项分组

= - \frac{π}{2} + \frac{4 πn}{2} + \frac{\frac{4 π}{3}}{2}

\frac{4 πn}{2} = 2 πn

\frac{4 πn}{2}

数字相除:

\frac{4}{2} = 2

= 2 πn

\frac{\frac{4 π}{3}}{2} = \frac{2 π}{3}

\frac{\frac{4 π}{3}}{2}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{4 π}{3 \cdot 2}

数字相乘:

3 \cdot 2 = 6

= \frac{4 π}{6}

约分:

2

= \frac{2 π}{3}

= - \frac{π}{2} + 2 πn + \frac{2 π}{3}

对同类项分组

= 2 πn - \frac{π}{2} + \frac{2 π}{3}

x = 2 πn - \frac{π}{2} + \frac{2 π}{3}

x = 2 πn - \frac{π}{2} + \frac{2 π}{3}

x = 2 πn - \frac{π}{2} + \frac{2 π}{3}

解

\frac{2 x + π}{2} = \frac{4 π}{3} + 2 πn : x = 2 πn - \frac{π}{2} + \frac{4 π}{3}

\frac{2 x + π}{2} = \frac{4 π}{3} + 2 πn

在两边乘以

2

\frac{2 x + π}{2} = \frac{4 π}{3} + 2 πn

在两边乘以

2

\frac{2 ( 2 x + π )}{2} = 2 \cdot \frac{4 π}{3} + 2 \cdot 2 πn

化简

\frac{2 ( 2 x + π )}{2} = 2 \cdot \frac{4 π}{3} + 2 \cdot 2 πn

化简

\frac{2 ( 2 x + π )}{2} : 2 x + π

\frac{2 ( 2 x + π )}{2}

数字相除:

\frac{2}{2} = 1

= 2 x + π

化简

2 \cdot \frac{4 π}{3} + 2 \cdot 2 πn : \frac{8 π}{3} + 4 πn

2 \cdot \frac{4 π}{3} + 2 \cdot 2 πn

2 \cdot \frac{4 π}{3} = \frac{8 π}{3}

2 \cdot \frac{4 π}{3}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{4 π 2}{3}

数字相乘:

4 \cdot 2 = 8

= \frac{8 π}{3}

2 \cdot 2 πn = 4 πn

2 \cdot 2 πn

数字相乘:

2 \cdot 2 = 4

= 4 πn

= \frac{8 π}{3} + 4 πn

2 x + π = \frac{8 π}{3} + 4 πn

2 x + π = \frac{8 π}{3} + 4 πn

2 x + π = \frac{8 π}{3} + 4 πn

将

π

到右边

2 x + π = \frac{8 π}{3} + 4 πn

两边减去

π

2 x + π - π = \frac{8 π}{3} + 4 πn - π

化简

2 x = \frac{8 π}{3} + 4 πn - π

2 x = \frac{8 π}{3} + 4 πn - π

两边除以

2

2 x = \frac{8 π}{3} + 4 πn - π

两边除以

2

\frac{2 x}{2} = \frac{\frac{8 π}{3}}{2} + \frac{4 πn}{2} - \frac{π}{2}

化简

\frac{2 x}{2} = \frac{\frac{8 π}{3}}{2} + \frac{4 πn}{2} - \frac{π}{2}

化简

\frac{2 x}{2} : x

\frac{2 x}{2}

数字相除:

\frac{2}{2} = 1

= x

化简

\frac{\frac{8 π}{3}}{2} + \frac{4 πn}{2} - \frac{π}{2} : 2 πn - \frac{π}{2} + \frac{4 π}{3}

\frac{\frac{8 π}{3}}{2} + \frac{4 πn}{2} - \frac{π}{2}

对同类项分组

= - \frac{π}{2} + \frac{4 πn}{2} + \frac{\frac{8 π}{3}}{2}

\frac{4 πn}{2} = 2 πn

\frac{4 πn}{2}

数字相除:

\frac{4}{2} = 2

= 2 πn

\frac{\frac{8 π}{3}}{2} = \frac{4 π}{3}

\frac{\frac{8 π}{3}}{2}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{8 π}{3 \cdot 2}

数字相乘:

3 \cdot 2 = 6

= \frac{8 π}{6}

约分:

2

= \frac{4 π}{3}

= - \frac{π}{2} + 2 πn + \frac{4 π}{3}

对同类项分组

= 2 πn - \frac{π}{2} + \frac{4 π}{3}

x = 2 πn - \frac{π}{2} + \frac{4 π}{3}

x = 2 πn - \frac{π}{2} + \frac{4 π}{3}

x = 2 πn - \frac{π}{2} + \frac{4 π}{3}

x = 2 πn - \frac{π}{2} + \frac{2 π}{3}, x = 2 πn - \frac{π}{2} + \frac{4 π}{3}

作图

流行的例子

sin(x)=sqrt(3)-sin(x)

sin (x) = 3 - sin (x)

cot(θ)=-(sqrt(3))/3

cot (θ) = - \frac{3}{3}

sin(x)-tan(x)=0

sin (x) - tan (x) = 0

sin(x+20)=cos(x)

sin (x + 2 0^{\circ}) = cos (x)

cos(x)-sqrt(3)sin(x)=1

cos (x) - 3 sin (x) = 1