What is the value of sin(-120) ?

The value of sin(-120) is -(sqrt(3))/2

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sin(-120)

sin (- 12 0^{\circ})

- \frac{3}{2}

Decimal Notation

- 0.86602 \dots

Solution steps

sin (- 12 0^{\circ})

Use the following property:

sin (- x) = - sin (x)

sin (- 12 0^{\circ}) = - sin (12 0^{\circ})

= - sin (12 0^{\circ})

Use the following trivial identity:

sin (12 0^{\circ}) = \frac{3}{2}

sin (12 0^{\circ})

sin (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{3}{2}

= - \frac{3}{2}

sin^{2} (6 0^{\circ})

sin (3 8^{\circ})

cos (- 10 5^{\circ})

\frac{2 ( cos ( 4 5 ^{\circ} ) ) ^{2} + 3 csc ( 3 7 ^{\circ} )}{2 tan ( 4 5 ^{\circ} )}

cot (24 0^{\circ})