The solution to 1-2/5-4/20 is 2/5

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1-2/5-4/20

Solution

1 - \frac{2}{5} - \frac{4}{20}

\frac{2}{5}

Solution steps

1 - \frac{2}{5} - \frac{4}{20}

\frac{4}{20} = \frac{1}{5}

Cancel the common factor:

4

\frac{1}{5}

= 1 - \frac{2}{5} - \frac{1}{5}

Follow the PEMDAS order of operations

Add and subtract (left to right)

1 - \frac{2}{5} - \frac{1}{5} : \frac{2}{5}

1 - \frac{2}{5} - \frac{1}{5}

1 - \frac{2}{5} = \frac{3}{5}

1 - \frac{2}{5}

Convert element to fraction:

1 = \frac{1 \cdot 5}{5}

= \frac{1 \cdot 5}{5} - \frac{2}{5}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 5 - 2}{5}

1 \cdot 5 - 2 = 3

1 \cdot 5 - 2

Multiply the numbers:

1 \cdot 5 = 5

= 5 - 2

Subtract the numbers:

5 - 2 = 3

= 3

= \frac{3}{5}

= \frac{3}{5} - \frac{1}{5}

\frac{3}{5} - \frac{1}{5} = \frac{2}{5}

\frac{3}{5} - \frac{1}{5}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{3 - 1}{5}

Subtract the numbers:

3 - 1 = 2

= \frac{2}{5}

= \frac{2}{5}

= \frac{2}{5}

(- 32 - 12 \times 6) \times 2 - 32 (- 3 + 7)

2 (- 1)^{3} - (- 1)^{2} - 6 (- 1) + 9

14 + 3 \times 7

\frac{14}{15} \div 2 - \frac{1}{5}

9 - (5) + (- 3) - (11)