What is (-2)\times (-2)\div [(+4)\times (-3)] ?

The solution to (-2)\times (-2)\div [(+4)\times (-3)] is -1/3

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(-2)\times (-2)\div [(+4)\times (-3)]

(- 2) \times (- 2) \div [(+ 4) \times (- 3)]

- \frac{1}{3}

Solution steps

(- 2) \times (- 2) \div [(4) \times (- 3)]

Follow the PEMDAS order of operations

Calculate within parentheses

[(4) \times (- 3)] : - 12

(4) \times (- 3)

Apply rule

(a) \times (- b) = - a \times b

(4) \times (- 3) = - 4 \times 3 = - 12

= - 12

= (- 2) \times (- 2) \div (- 12)

Multiply and divide (left to right)

(- 2) \times (- 2) \div (- 12) : \frac{4}{( - 12 )}

(- 2) \times (- 2) \div (- 12)

Apply rule

(- a) \times (- b) = a \times b

(- 2) \times (- 2) = 2 \times 2 = 4

= 4 \div (- 12)

Apply rule

a \div (- b) = - a \div b

4 \div (- 12) = - 4 \div 12 = \frac{4}{( - 12 )}

= \frac{4}{( - 12 )}

= \frac{4}{( - 12 )}

Simplify

\frac{4}{( - 12 )} : - \frac{1}{3}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{4}{12}

Cancel the common factor:

4

= - \frac{1}{3}

1 0^{3} + 1 0^{3}

(8 \times 9 + 3 - 45) \div 3 + 5

18 \div 3 - 7 + 2 \times 5

8/2 (2 + 4)

8 \div 3 + 1 \div 2 + 6 \div 4

What is (-2)\times (-2)\div [(+4)\times (-3)] ?
The solution to (-2)\times (-2)\div [(+4)\times (-3)] is -1/3