What is (-7\div 2)\times (4\div 5) ?

The solution to (-7\div 2)\times (4\div 5) is -14/5

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(-7\div 2)\times (4\div 5)

(- 7 \div 2) \times (4 \div 5)

- \frac{14}{5}

Solution steps

(- 7 \div 2) \times (4 \div 5)

Follow the PEMDAS order of operations

Calculate within parentheses

(- 7 \div 2) : \frac{- 7}{2}

- 7 \div 2

- 7 \div 2 = \frac{- 7}{2}

= \frac{- 7}{2}

= \frac{- 7}{2} \times (4 \div 5)

Calculate within parentheses

(4 \div 5) : \frac{4}{5}

4 \div 5

4 \div 5 = \frac{4}{5}

= \frac{4}{5}

= \frac{- 7}{2} \times \frac{4}{5}

Multiply and divide (left to right)

\frac{- 7}{2} \times \frac{4}{5} : - \frac{14}{5}

\frac{- 7}{2} \times \frac{4}{5}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

\frac{- 7}{2} = - \frac{7}{2}

= - \frac{7}{2} \cdot \frac{4}{5}

- \frac{7}{2} \cdot \frac{4}{5} = - \frac{14}{5}

- \frac{7}{2} \cdot \frac{4}{5}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

\frac{7}{2} \cdot \frac{4}{5} = \frac{7 \cdot 4}{2 \cdot 5}

= - \frac{7 \cdot 4}{2 \cdot 5}

Cancel

\frac{7 \cdot 4}{2 \cdot 5} : \frac{14}{5}

\frac{7 \cdot 4}{2 \cdot 5}

Factor the number:

4 = 2 \cdot 2

= \frac{7 \cdot 2 \cdot 2}{2 \cdot 5}

Cancel the common factor:

2

= \frac{7 \cdot 2}{5}

Multiply the numbers:

7 \cdot 2 = 14

= \frac{14}{5}

= - \frac{14}{5}

= - \frac{14}{5}

= - \frac{14}{5}

2^{13} - 1

1212121212 5^{2} - 1212121212 4^{2}

- 12 (1)^{2}

- 2 (- 3 \frac{- 1}{3}) + 5

1 \div 2 \div 3 \div 7

What is (-7\div 2)\times (4\div 5) ?
The solution to (-7\div 2)\times (4\div 5) is -14/5