What is (-5)^0+[(2)^4+(-2)^3] ?

The solution to (-5)^0+[(2)^4+(-2)^3] is 9

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(-5)^0+[(2)^4+(-2)^3]

(- 5)^{0} + [(2)^{4} + (- 2)^{3}]

9

Solution steps

(- 5)^{0} + [(2)^{4} + (- 2)^{3}]

Follow the PEMDAS order of operations

Calculate within parentheses

[(2)^{4} + (- 2)^{3}] : 8

(2)^{4} + (- 2)^{3}

Calculate exponents

(2)^{4} : 16

(2)^{4}

(2)^{4} = 16

= 16

= 16 + (- 2)^{3}

Calculate exponents

(- 2)^{3} : - 8

(- 2)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 2)^{3} = - 2^{3} = - 8

= - 8

= 16 - 8

Add and subtract (left to right)

16 - 8 : 8

16 - 8

16 - 8 = 8

= 8

= 8

= (- 5)^{0} + 8

Calculate exponents

(- 5)^{0} : 1

(- 5)^{0}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 5)^{0} = 5^{0} = 1

= 1

= 1 + 8

Add and subtract (left to right)

1 + 8 : 9

1 + 8

1 + 8 = 9

= 9

= 9

3 - 1 - 2

3 - 1 + 3

\frac{3}{4} - (\frac{1}{2} + \frac{2}{3})

2 + 3^{2} - 4

2^{50} + 2^{50}